Question

在声明结尾处使用HAVING子句时，我们无法弄清楚为什么我们不能COUNT。

此语句返回结果：

SELECT lid, cid, title, url, description, date, hits, downloadratingsummary, totalvotes, totalcomments, filesize, version, homepage, ns_compat, ns_des_img, ( (2.0 * (MATCH(title) AGAINST ('fsx concorde' IN BOOLEAN MODE))) + (1.0 * (MATCH(description) AGAINST ('fsx concorde' IN BOOLEAN MODE))) + (0.5 * (MATCH(url) AGAINST ('fsx concorde' IN BOOLEAN MODE))) ) AS relevance FROM nuke_downloads_downloads WHERE ( MATCH(title,description,url) AGAINST ('fsx concorde' IN BOOLEAN MODE) ) HAVING relevance > 3.0 ORDER BY relevance DESC

此语句不返回任何内容

SELECT COUNT(*) as num, lid, cid, title, url, description, date, hits, downloadratingsummary, totalvotes, totalcomments, filesize, version, homepage, ns_compat, ns_des_img, ( (2.0 * (MATCH(title) AGAINST ('fsx concorde' IN BOOLEAN MODE))) + (1.0 * (MATCH(description) AGAINST ('fsx concorde' IN BOOLEAN MODE))) + (0.5 * (MATCH(url) AGAINST ('fsx concorde' IN BOOLEAN MODE))) ) AS relevance FROM nuke_downloads_downloads WHERE ( MATCH(title,description,url) AGAINST ('fsx concorde' IN BOOLEAN MODE) ) HAVING relevance > 3.0 ORDER BY relevance DESC

我们在这里遗漏了什么吗？

非常感谢您的帮助，并提前感谢您。

Answer 1

如果只想要第一个查询返回的行数，可以将查询封装到派生表中。

您可以跳过relevance列表和SELECT列表中ORDER BY以外的所有列：

SELECT COUNT(*)
FROM
  ( SELECT ( (2.0 * (MATCH ... ) AS relevance 
    FROM ...                                     -- unchanged
    WHERE ...                                    -- unchanged
    HAVING relevance > 3.0
                                                 -- ORDER BY removed    
  ) AS t ;

在MySQL中使用带有HAVING子句的COUNT

1 个答案: