我写了以下代码：
NSURL *url = [NSURL URLWithString:@"http://api.twitter.com/1.1/users/show.json"];
NSDictionary *params = [NSDictionary dictionaryWithObjectsAndKeys:username, @"screen_name" ,[[controller.engine accessToken] secret]];
TWRequest *request = [[TWRequest alloc] initWithURL:url parameters:params requestMethod:TWRequestMethodGET];
[request performRequestWithHandler:
^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
if (responseData) {
NSDictionary *user = [NSJSONSerialization JSONObjectWithData:responseData
options:NSJSONReadingAllowFragments
error:NULL];
NSString *profileImageUrl = [user objectForKey:@"profile_image_url"];
NSLog(@"%@",profileImageUrl);
}
}];
但我总是得到Bad authentication错误。我觉得我错过了什么。有人请检查我的代码吗？或者提供任何建议来检索Twitter用户个人资料图片？
由于
答案 0 :(得分：8)
您是否考虑过使用第三方Twitter引擎？我已经使用FHSTwitterEngine取得了相当大的成功，而且它似乎正在积极发展中。
要绘制个人资料图片，您可以执行以下操作：
[[FHSTwitterEngine sharedEngine]permanentlySetConsumerKey:@"<consumer_key>" andSecret:@"<consumer_secret>"];
[[FHSTwitterEngine sharedEngine]showOAuthLoginControllerFromViewController:self
withCompletion:^(BOOL success) {
if (success) {
UIImage *profileImg = [[FHSTwitterEngine sharedEngine] getProfileImageForUsername:@"<username>" andSize:size];
}
}];
答案 1 :(得分：1)
这是我过去尝试过的
[PFTwitterUtils logInWithBlock:^(PFUser *user, NSError *error) {
if (!user) {
NSLog(@"Uh oh. The user cancelled the Twitter login.");
[[NSNotificationCenter defaultCenter] postNotificationName:notificationUserLoginFailed
object:error];
return;
} else {
// TODO find a way to fetch details with Twitter..
NSString * requestString = [NSString stringWithFormat:@"https://api.twitter.com/1.1/users/show.json?screen_name=%@", user.username];
NSURL *verify = [NSURL URLWithString:requestString];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:verify];
[[PFTwitterUtils twitter] signRequest:request];
NSURLResponse *response = nil;
NSData *data = [NSURLConnection sendSynchronousRequest:request
returningResponse:&response
error:&error];
if ( error == nil){
NSDictionary* result = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&error];
_NSLog(@"%@",result);
[user setObject:[result objectForKey:@"profile_image_url_https"]
forKey:@"picture"];
// does this thign help?
[user setUsername:[result objectForKey:@"screen_name"]];
NSString * names = [result objectForKey:@"name"];
NSMutableArray * array = [NSMutableArray arrayWithArray:[names componentsSeparatedByString:@" "]];
if ( array.count > 1){
[user setObject:[array lastObject]
forKey:@"last_name"];
[array removeLastObject];
[user setObject:[array componentsJoinedByString:@" " ]
forKey:@"first_name"];
}
[user saveInBackground];
}
[[NSNotificationCenter defaultCenter] postNotificationName:notificationUserDidLogin
object:nil];
return;
}
}];
答案 2 :(得分：1)
请注意，您应该登录iOS设备以获取此功能：
- (void)signIniwthTwitter
{
if ([TWTweetComposeViewController canSendTweet])
{
// Set up the built-in twitter composition view controller.
TWTweetComposeViewController *tweetViewController = [[TWTweetComposeViewController alloc] init];
// Create the completion handler block.
[tweetViewController setCompletionHandler:^(TWTweetComposeViewControllerResult result) {
[self dismissModalViewControllerAnimated:YES];
}];
// Present the tweet composition view controller modally.
[self presentModalViewController:tweetViewController animated:YES];
}
else
{
[self getTwitterAccountDetails];
}
}
- (void) getTwitterAccountDetails
{
[DejalBezelActivityView activityViewForView:self.navigationController.navigationBar.superview];
self.view.userInteractionEnabled = NO;
self.connectionstatusLabel.text = @"Getting user details....";
// Create an account store object.
ACAccountStore *accountStore = [[ACAccountStore alloc] init];
// Create an account type that ensures Twitter accounts are retrieved.
ACAccountType *accountType = [accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
// Request access from the user to use their Twitter accounts.
[accountStore requestAccessToAccountsWithType:accountType withCompletionHandler:^(BOOL granted, NSError *error) {
#pragma unused (error)
if(granted) {
// Get the list of Twitter accounts.
NSArray *accountsArray = [accountStore accountsWithAccountType:accountType];
// For the sake of brevity, we'll assume there is only one Twitter account present.
// You would ideally ask the user which account they want to tweet from, if there is more than one Twitter account present.
if ([accountsArray count] > 0) {
// Grab the initial Twitter account to tweet from.
ACAccount *twitterAccount = [accountsArray objectAtIndex:0];
NSLog(@"Account details %@",twitterAccount);
_userid = [[twitterAccount valueForKey:@"properties"] valueForKey:@"user_id"];
_screenName = [twitterAccount valueForKey:@"username"];
NSLog(@"user id %@",_userid);
[self getProfileDetailsFromTwitter];
}
}
}];
}
- (void) getProfileDetailsFromTwitter
{
self.connectionstatusLabel.text = @"Getting user profile details....";
NSURL *twitterURL = [NSURL URLWithString:[NSString stringWithFormat:@"https://api.twitter.com/1/users/show.json?user_id=%@&include_entities=true",_userid]];
TWRequest *postRequest = [[TWRequest alloc] initWithURL:twitterURL parameters:nil requestMethod:TWRequestMethodGET];
// Perform the request created above and create a handler block to handle the response.
[postRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
NSString *output;
if ([urlResponse statusCode] == 200) {
// Parse the responseData, which we asked to be in JSON format for this request, into an NSDictionary using NSJSONSerialization.
NSError *jsonParsingError = nil;
NSDictionary *publicTimeline = [NSJSONSerialization JSONObjectWithData:responseData options:0 error:&jsonParsingError];
NSLog(@"Twiiter Profile Deatils %@",publicTimeline);
_twitterUserProfileDetails = [[MobileYakUser alloc]init];
_twitterUserProfileDetails.firstName = [publicTimeline objectForKey:@"name"];
_twitterUserProfileDetails.lastName = [publicTimeline objectForKey:@"name"];
output = [NSString stringWithFormat:@"HTTP response status: %i\nPublic timeline:\n%@", [urlResponse statusCode], publicTimeline];
NSURL *url =
[NSURL URLWithString:@"http://api.twitter.com/1/users/profile_image/"];
NSMutableDictionary *params = [[NSMutableDictionary alloc]init];
[params setValue:_screenName forKey:@"screen_name"];
[params setValue:@"original" forKey:@"size"];
TWRequest *request = [[TWRequest alloc] initWithURL:url
parameters:params
requestMethod:TWRequestMethodGET];
[request performRequestWithHandler:
^(NSData *imageresponseData, NSHTTPURLResponse *imageFetchurlResponse, NSError *imageerror) {
#pragma unused (imageFetchurlResponse,imageerror)
if (imageresponseData) {
self.connectionstatusLabel.text = @"Getting user profile image....";
UIImage *image = [UIImage imageWithData:imageresponseData];
_twitterUserProfileDetails.profileImage = image;
self.connectionstatusLabel.text = @"Please fill up following fields for login";
self.view.userInteractionEnabled = YES;
[DejalActivityView removeView];
}
}];
}
else {
output = [NSString stringWithFormat:@"HTTP response status: %i\n", [urlResponse statusCode]];
}
}];
}
答案 3 :(得分：1)
// Twitter使用块获取ios方法的数据 https://www.dropbox.com/sh/vdxtw3x1coyyj8x/AADw6cyYNjeHM-77GqAyBZ5oa?dl=0
答案 4 :(得分：0)
这是profile_image_url_https;）
我们可以在不使用Twitter sdk的情况下访问个人资料图片。在iOS中使用社交框架我们可以使用它。
我使用ACAccounts代替Twitter IOS SDK，如MGTwitterEngine等.......
将使用iPhone设置中提供的Twitter帐户。
if(!accountStore)
accountStore = [[ACAccountStore alloc] init];
ACAccountType *accountType = [accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
[accountStore
requestAccessToAccountsWithType:accountType
options:NULL
completion:^(BOOL granted, NSError *error) {
if (granted) {
// Step 2: Create a request
NSArray *accountsArray = [accountStore accountsWithAccountType:accountType];
self.twitterAccount = [accountsArray objectAtIndex:0];
// NSString *userID = [[twitterAccount valueForKey:@"properties"] valueForKey:@"user_id"];
NSURL *url = [NSURL URLWithString:@"https://api.twitter.com/1.1/users/show.json"];
NSDictionary *params = @{@"screen_name" : twitterAccount.username
};
SLRequest *request =
[SLRequest requestForServiceType:SLServiceTypeTwitter
requestMethod:SLRequestMethodGET
URL:url
parameters:params];
// Attach an account to the request
[request setAccount:[accountsArray lastObject]];
// Step 3: Execute the request
[request performRequestWithHandler:^(NSData *responseData,
NSHTTPURLResponse *urlResponse,
NSError *error) {
if (responseData) {
if (urlResponse.statusCode >= 200 && urlResponse.statusCode < 300) {
[self performSelectorOnMainThread:@selector(twitterdetails:)
withObject:responseData waitUntilDone:YES];
}
else {
NSLog(@"The response status code is %d", urlResponse.statusCode);
}
}
}];
}
else
{
dispatch_async(dispatch_get_main_queue(), ^{
[self dismissError:@"Please set up your twitter account in iphone settings"];
});
}
}];
-(void)twitterdetails:(NSData *)responseData {
NSError* error = nil;
NSDictionary* json = [NSJSONSerialization
JSONObjectWithData:responseData //1
options:NSJSONReadingAllowFragments
error:&error];
NSString *name = [json objectForKey:@"name"];
NSString *scrnm = [json objectForKey:@"screen_name"];
NSString *twitterid = [json objectForKey:@"id"];
NSString *prof_img = [json objectForKey:@"profile_image_url"];
NSString *location = [json objectForKey:@"location"];
}
答案 5 :(得分：0)
试试这个，这是使用fabricSDK
获取用户个人资料的最新信息 -(void)usersShow:(NSString *)userID
{
NSString *statusesShowEndpoint = @"https://api.twitter.com/1.1/users/show.json";
NSDictionary *params = @{@"user_id": userID};
NSError *clientError;
NSURLRequest *request = [[[Twitter sharedInstance] APIClient]
URLRequestWithMethod:@"GET"
URL:statusesShowEndpoint
parameters:params
error:&clientError];
if (request) {
[[[Twitter sharedInstance] APIClient]
sendTwitterRequest:request
completion:^(NSURLResponse *response,
NSData *data,
NSError *connectionError) {
if (data) {
// handle the response data e.g.
NSError *jsonError;
NSDictionary *json = [NSJSONSerialization
JSONObjectWithData:data
options:0
error:&jsonError];
NSLog(@"%@",[json description]);
}
else {
NSLog(@"Error code: %ld | Error description: %@", (long)[connectionError code], [connectionError localizedDescription]);
}
}];
}
else {
NSLog(@"Error: %@", clientError);
}
}