OpenAL.org&&创意开发网站已关闭。我选择了替代版本OpenAL Soft。我很担心,因为在OpenAL Soft的二进制安装中我找不到alut.h
标头。 alut.h
标题的目的是什么?如果我有一个标题会改变什么?
哦还有一件事。我从中获取了一个简单的代码(描述中的ZIP)tutorial并使用C语言进行翻译。我实际上得到一个声音,但它变形了。我想知道我的代码出了什么问题?
#include <stdio.h>
#include <stdlib.h>
#include <windows.h>
#include <OPENAL/al.h>
#include <OPENAL/alc.h>
int main(int argc, char *argv[])
{
FILE *fp = NULL;
fp=fopen("WAVE/Sound.wav","rb");
char type[4];
DWORD size,chunkSize;
short formatType,channels;
DWORD sampleRate,avgBytesPerSec;
short bytesPerSample,bitsPerSample;
DWORD dataSize;
fread(type,sizeof(char),4,fp);
fread(&size, sizeof(DWORD),1,fp);
fread(type, sizeof(char),4,fp);
fread(type,sizeof(char),4,fp);
fread(&chunkSize,sizeof(DWORD),1,fp);
fread(&formatType,sizeof(short),1,fp);
fread(&channels,sizeof(short),1,fp);
fread(&sampleRate,sizeof(DWORD),1,fp);
fread(&avgBytesPerSec,sizeof(DWORD),1,fp);
fread(&bytesPerSample,sizeof(short),1,fp);
fread(&bitsPerSample,sizeof(short),1,fp);
fread(type,sizeof(char),4,fp);
fread(&dataSize,sizeof(DWORD),1,fp);
ALCdevice *device;
ALCcontext *context;
device = alcOpenDevice(NULL);
context = alcCreateContext(device, NULL);
alcMakeContextCurrent(context);
ALuint source;
ALuint buffer;
ALuint frequency=sampleRate;
ALenum format=0;
alGenBuffers(1, &buffer);
alGenSources(1, &source);
if(bitsPerSample == 8)
{
if(channels == 1)
format = AL_FORMAT_MONO8;
else if(channels == 2)
format = AL_FORMAT_STEREO8;
}
else if(bitsPerSample == 16)
{
if(channels == 1)
format = AL_FORMAT_MONO16;
else if(channels == 2)
format = AL_FORMAT_STEREO16;
}
alBufferData(buffer, format, "24641", dataSize, frequency);
//Sound setting variables
ALfloat SourcePos[] = { 0.0, 0.0, 0.0 }; //Position of the source sound
ALfloat SourceVel[] = { 0.0, 0.0, 0.0 }; //Velocity of the source sound
ALfloat ListenerPos[] = { 0.0, 0.0, 0.0 }; //Position of the listener
ALfloat ListenerVel[] = { 0.0, 0.0, 0.0 }; //Velocity of the listener
ALfloat ListenerOri[] = { 0.0, 0.0, -1.0, 0.0, 1.0, 0.0 }; //Orientation of the listener
alListenerfv(AL_POSITION, ListenerPos); //Set position of the listener
alListenerfv(AL_VELOCITY, ListenerVel); //Set velocity of the listener
alListenerfv(AL_ORIENTATION, ListenerOri); //Set orientation of the listener
alSourcei (source, AL_BUFFER, buffer); //Link the buffer to the source
alSourcef (source, AL_PITCH, 1.0f ); //Set the pitch of the source
alSourcef (source, AL_GAIN, 1.0f ); //Set the gain of the source
alSourcefv(source, AL_POSITION, SourcePos); //Set the position of the source
alSourcefv(source, AL_VELOCITY, SourceVel); //Set the velocity of the source
alSourcei (source, AL_LOOPING, AL_FALSE ); //Set if source is looping sound
//PLAY
alSourcePlay(source); //Play the sound buffer linked to the source
system("PAUSE"); //Pause to let the sound play
//Clean-up
fclose(fp); //Delete the sound data buffer
alDeleteSources(1, &source); //Delete the OpenAL Source
alDeleteBuffers(1, &buffer); //Delete the OpenAL Buffer
alcMakeContextCurrent(NULL); //Make no context current
alcDestroyContext(context); //Destroy the OpenAL Context
alcCloseDevice(device); //Close the OpenAL Device
return EXIT_SUCCESS;
}
答案 0 :(得分:4)
alBufferData(buffer, format, "24641", dataSize, frequency);
您将“24641”字节数组作为声音传递。除了它非常非常快速的声音 - dataSize肯定会更大,所以你实际上阅读更多。并且玩这个垃圾。
我不清楚WAV格式,正如我所见 - 你不是从文件中读取实际的波形数据,只是它的标题。检查WAV文档。在标题之后猜测你需要分配dataSize字节数组并从文件的其余部分读取它,然后将它传递给alBufferData。
不,你的代码不使用alut,所以你不需要它。它是处理上下文创建的小型实用程序库 - 您自己完成。
答案 1 :(得分:1)
alutLoadWAVFile("XXX.wav", &format, &data, &size, &freq, &loop);