Question

这是我的查询

$offers_with_limit = $db->query("
SELECT *
FROM `offers`
WHERE `countries` LIKE '%'?'%'
  AND `category` = '$query2'
  AND NOT EXISTS
    (SELECT *
     FROM completed
     WHERE completed.offer_id = offers.id
       AND completed.user = ?)
  AND NOT EXISTS
    (SELECT *
     FROM pending
     WHERE pending.offer_id = offers.id
       AND pending.user = ?)
  AND NOT EXISTS
    (SELECT *
     FROM ignored
     WHERE ignored.offer_id = offers.id
       AND ignored.user = ?)
  AND `active` = '1'
  AND `hard_incent` > '0'
ORDER BY `hard_incent` ASC,
         `date_added` DESC LIMIT $startpoint,$limit
    ");

显然，它只会显示大于0的行，但我还需要它继续显示大于等于0的行之后的行，如果我不添加{{1然后它显示首先等于0的行，因为它们是hard_incent > '0'顺序。

Answer 1

使用：

ORDER BY hard_incent <= 0, hard_incent ASC, date_added DESC

对于大于0的行，第一次比较将为0;对于小于或等于0的行，第一次比较将为1，因此它将首先显示更大的行。然后在这两个集合中，它将按hard_incent和date_added排序。

显示值大于0的行，然后显示等于0的行

1 个答案: