Oracle Apex饼图SQL语句

Question

我对SQL＆amp; Apex，但我需要一个声明，我真的很感谢你对此的帮助。 Apex饼图的语法是：

SELECT link, label, value

我的表看起来像这些简单的草图：

+------+-----------+---------+
| ID   | Company   | Item    |
+------+-----------+---------+
| 1    | AAA       |Some     |
| 2    | BB        |Stuff    |
| 3    | BB        |Not      |
| 4    | CCCC      |Important|
| 5    | AAA       |For      |
| 6    | DDDDD     |Question?|
+------+-----------+---------+

我想显示公司的百分比。

问题：所有少于5件商品的公司应该合并为一个“其他”列。对我来说，困难在于将“不重要”的公司结合起来。

到目前为止，我的发言如下：

SELECT null link, 
company label, 
COUNT(ID) value FROM table HAVING COUNT(ID) > 5 GROUP BY company

这是一个精彩的图表草图。 ：D

感谢您的想法！

Answer 1

我没有让SQL Developer出现在我面前，但是这个（或者一个接近的变体）应该适合你：

WITH company_count
  AS (
      SELECT CASE
                WHEN count(*) < 5
                THEN 'Other'
                ELSE company
              END AS company_name,
             id
        FROM tablename
      ),
      company_group
  AS (
      SELECT company_name,
             count(id) item_count
        FROM company_count
       GROUP BY company_name
     )
SELECT NULL AS link,
       company_name AS label,
       item_count AS value
  FROM company_group;

希望它有所帮助！

Answer 2

好的伙计们，我找到了用例的答案。它与Ollies的回答非常相似。再次感谢您的帮助！

 WITH sq1 AS (SELECT company, COUNT (*) AS count FROM 
 (SELECT CASE WHEN COUNT (*) OVER  (Partition By company) > 5 THEN company
 ELSE 'other' END AS company, id FROM table) GROUP BY company)

 SELECT null link, company label, count value FROM sq1 ORDER BY count desc