我正在尝试使用Http中的Rss XML,我使用了这个数学代码:
public String getXMLfromUrl(String url){
String xml = null;
try{
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpclient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
xml = EntityUtils.toString(httpEntity);
}catch(Exception e){
Log.e(" getXMLfromUrl : "," ",e);
}
return xml;
}
public Document getDomElement(String xml){
Document doc = null;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try{
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
doc = db.parse(xml);
doc.getDocumentElement().normalize();
}catch(Exception e){
Log.e(" getDomElement : "," ",e);
}
return doc;
}
但我有一个问题,第一个mathod不会返回所有XML String,所以String不是XML格式,我认为我的XML Stream太长或者我包含/ n或者可能但是包含阿拉伯字符,所以第二个Mathod抛出java.net.malformedurlexception协议找不到android,或者说我觉得....
请求帮助我