像和文本结果一样

Question

我正在试图弄清楚如何在MySQL中运行将执行以下操作的查询：

1. 搜索任何以5开头的数字，并将结果放在标有classRef的列中，结果文字为FOO
2. 如果该数字以5以外的任何数字开头，则输出到列classRef，结果文本为BAR。

这是我到目前为止所做的：

SELECT
ara.AddressNumber AS ExternalID,
ara.AddressNumber as tranId,
cus.Name AS customerRef,
cus.ExternalID LIKE '5%' AS classRef,
cus.ExternalID NOT LIKE '5%' AS classRef2,
'1' AS itemLine_quantity,
'0' AS itemLine_salesPrice

FROM
adrun_copy ara,
customers_copy cus

WHERE
ara.AAccountNumber = cus.ExternalID

Answer 1

CASE WHEN cus.ExternalID LIKE '5%' THEN 'FOO' ELSE 'BAR' END As classRef

如果那真的是像int那样的数字列，你可能需要CAST首先将它变为varchar ...不确定MySql的规则。