Question

我正在尝试使用suds python包发送soap请求，如下所示：

from suds.client import Client
WSDL_URL = 'file:/home/Documents/soap/getttt.wsdl'
client = Client(WSDL_URL, cache=None)
result = client.service.GET_TTT(H_ID="01",
                                TTT_ID="44825955",
                                VERSION_DATE="2010-12-01",
                                ACC="B9800B4930543BC4FB305124EDFF7846")
print result

使用带有http uri的简单wsdl可以正常工作，但是我需要使用文件协议加载这个wsdl，这个wsdl要复杂得多。它导入xsd文件，如下所示：

   <types>
      <xsd:schema>
         <xsd:import schemaLocation="GET_TTT.xsd" namespace="http://example.com"/>
         <xsd:import schemaLocation="TTT_TABLES.xsd" namespace="http://example.com"/>
      </xsd:schema>
   </types>

此错误消息失败：

  File "suds_client.py", line 17, in <module>
    ACC="B9800B4930543BC4FB305124EDFF7846")
  File "python2.7/site-packages/suds/client.py", line 542, in __call__
    return client.invoke(args, kwargs)
  File "python2.7/site-packages/suds/client.py", line 602, in invoke
    result = self.send(soapenv)
  File "python2.7/site-packages/suds/client.py", line 637, in send
    reply = transport.send(request)
  File "python2.7/site-packages/suds/transport/https.py", line 64, in send
    return  HttpTransport.send(self, request)
  File "python2.7/site-packages/suds/transport/http.py", line 77, in send
    fp = self.u2open(u2request)
  File "python2.7/site-packages/suds/transport/http.py", line 118, in u2open
    return url.open(u2request, timeout=tm)
  File "/usr/lib/python2.7/urllib2.py", line 404, in open
    response = self._open(req, data)
  File "/usr/lib/python2.7/urllib2.py", line 422, in _open
    '_open', req)
  File "/usr/lib/python2.7/urllib2.py", line 382, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.7/urllib2.py", line 1214, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/usr/lib/python2.7/urllib2.py", line 1184, in do_open
    raise URLError(err)
urllib2.URLError: <urlopen error [Errno 111] Connection refused>

任何想法如何调试这个？我是否需要使用ImportDoctor来加载xsd文件或者是否自动加载它们？如果我这样做，那么如何加载所有的xsd文件？我能够使用名为soapUI的软件从该wsdl发送请求。感谢

Answer 1

如果我只是使用字符串作为参数，它会抱怨参数并说

urllib2.URLError: <urlopen error [Errno 111] Connection refused>

看着：

<xs:complexType name="T_GET_TTT">
                <xs:attribute name="HES_ID" type="com:hesHesID" use="required"/>
                <xs:attribute name="TTT_ID" type="xs:string" use="required"/>
                <xs:attribute name="VERSION_DATE" type="xs:date" use="required"/>
                <xs:attribute name="ACC" type="xs:hexBinary" use="required"/>
</xs:complexType>

然后我决定使用从医生那里导入xml模式的正确类型：

imp = Import('http://www.w3.org/2001/XMLSchema')
d = ImportDoctor(imp)
imp.filter.add('http://aa')
client = Client(WSDL_URL, cache=None, doctor=d)
print client
client.factory.create('xs:string')

我的print命令显示我有xs：string类型：但是我得到了这个错误：

例外：前缀（xs）未解决

为什么它认为xs不是前缀而是类型名称的一部分的任何想法？

从python发送soap请求

1 个答案: