Question

基本上我已经完成了一个应用程序。我唯一的问题是ATM应用程序的设计只考虑了4英寸显示器。当在3.5英寸的模拟器中运行时，应用程序中缺少.5英寸（显然）。

那么，我的问题是，我如何在Xcode 5中为不同的屏幕尺寸设置不同的故事板？

我知道在使用以下代码之前：

-(void)initializeStoryBoardBasedOnScreenSize {

if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
{    // The iOS device = iPhone or iPod Touch


CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;

if (iOSDeviceScreenSize.height == 480)
{   // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)

    // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone35
    UIStoryboard *Main_iPhone2 = [UIStoryboard storyboardWithName:@"Main_iPhone3" bundle:nil];

    // Instantiate the initial view controller object from the storyboard
    UIViewController *initialViewController = [Main_iPhone2 instantiateInitialViewController];

    // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
    self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

    // Set the initial view controller to be the root view controller of the window object
    self.window.rootViewController  = initialViewController;

    // Set the window object to be the key window and show it
    [self.window makeKeyAndVisible];
}

if (iOSDeviceScreenSize.height == 568)
{   // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)

    // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
    UIStoryboard *Main_iPhone = [UIStoryboard storyboardWithName:@"Main_iPhone" bundle:nil];

    // Instantiate the initial view controller object from the storyboard
    UIViewController *initialViewController = [Main_iPhone instantiateInitialViewController];

    // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
    self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

    // Set the initial view controller to be the root view controller of the window object
    self.window.rootViewController  = initialViewController;

    // Set the window object to be the key window and show it
    [self.window makeKeyAndVisible];
}

} else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)

{   // The iOS device = iPad

UISplitViewController *splitViewController = (UISplitViewController *)self.window.rootViewController;
UINavigationController *navigationController = [splitViewController.viewControllers lastObject];
splitViewController.delegate = (id)navigationController.topViewController;

}
}

但与Xcode 5的交易，以及我认为此代码无法正常工作的原因在于，您的项目中有一个部分通常会在整个特定设备类型中建立故事板作为主要部分。

所以，要么采用不同的方式来完成整个单独的故事情节，要么就是我对代码做错了。以下代码显然位于AppDelegate.m文件下...所以不要认为我有任何错误。

谢谢，真的很有帮助，非常感谢。我真的想提交这个应用程序!!!

此致，Patricio

Answer 1

在我的App委托中的- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions方法中，我有这个块：

// Override point for customization after application launch.
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone){
    UIStoryboard *storyBoard;

    CGSize result = [[UIScreen mainScreen] bounds].size;
    CGFloat scale = [UIScreen mainScreen].scale;
    result = CGSizeMake(result.width * scale, result.height * scale);

    if(result.height != 1136){
        storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard35" bundle:nil];
        UIViewController *initViewController = [storyBoard instantiateInitialViewController];
        [self.window setRootViewController:initViewController];
    }
}

对于4英寸屏幕，它会覆盖我的默认MainStoryboard，并加载我的3.5英寸屏幕故事板。在我的项目中，我仍然将MainStoryboard（4英寸屏幕版本）定义为主界面。

这适用于Xcode 5.它在一个发货应用程序中，所以它应该可以正常工作。

有不同屏幕尺寸的单独故事板？

1 个答案: