我想解析这些Json的回应:
{
"MyResponse": {
"count": 3,
"listTsm": [{
"id": "b90c6218-73c8-30bd-b532-5ccf435da766",
"simpleid": 1,
"name": "vignesh1"
},
{
"id": "b90c6218-73c8-30bd-b532-5ccf435da766",
"simpleid": 2,
"name": "vignesh2"
},
{
"id": "b90c6218-73c8-30bd-b532-5ccf435da766",
"simpleid": 3,
"name": "vignesh3"
}]
}
}
我尝试使用SIMPLE JSON解析器,但这对我不起作用:
Object obj = parser.parse(resp);
JSONObject jsonObject = (JSONObject) obj;
JSONArray response = (JSONArray) jsonObject.get("MyResponse");
//JSONArray arr=new JSONArray(yourJSONresponse);
ArrayList<String> list = new ArrayList<String>();
for(int i=0; i<response.size(); i++){
list.add(response.get(i)("name"));
}
答案 0 :(得分:21)
public static void main(String[] args) throws JSONException {
String jsonString = "{" +
" \"MyResponse\": {" +
" \"count\": 3," +
" \"listTsm\": [{" +
" \"id\": \"b90c6218-73c8-30bd-b532-5ccf435da766\"," +
" \"simpleid\": 1," +
" \"name\": \"vignesh1\"" +
" }," +
" {" +
" \"id\": \"b90c6218-73c8-30bd-b532-5ccf435da766\"," +
" \"simpleid\": 2," +
" \"name\": \"vignesh2\"" +
" }," +
" {" +
" \"id\": \"b90c6218-73c8-30bd-b532-5ccf435da766\"," +
" \"simpleid\": 3," +
" \"name\": \"vignesh3\"" +
" }]" +
" }" +
"}";
JSONObject jsonObject = new JSONObject(jsonString);
JSONObject myResponse = jsonObject.getJSONObject("MyResponse");
JSONArray tsmresponse = (JSONArray) myResponse.get("listTsm");
ArrayList<String> list = new ArrayList<String>();
for(int i=0; i<tsmresponse.length(); i++){
list.add(tsmresponse.getJSONObject(i).getString("name"));
}
System.out.println(list);
}
}
输出:
[vignesh1, vignesh2, vignesh3]
评论:我没有添加验证
<强> [编辑] 强>
加载json String的其他方法
JSONObject obj= new JSONObject();
JSONObject jsonObject = obj.fromObject(jsonString);
....
答案 1 :(得分:-2)
你可以做到:
JSONObject response = new JSONObject(resp);
然后你可以根据变量的类型使用:
int count = response.getint("count");
或
JSONArray tsm = response.getJSONArray(listTsm)
然后,如果你想遍历里面的对象,你只需使用for for。