Question

我的数组有什么问题，我得到错误信息'array'，这并没有说明它有什么问题。我看不出它有什么问题，它没有将图片上传到目标文件夹，只是希望有人可以帮助我。

<?php

$s = "-";

 $sqlName=mysql_query("SELECT * FROM business WHERE email='$login_bus' LIMIT 1")or die   
 ("Sorry we have a mysql error!");

 $row=mysql_fetch_array($sqlName);$busID=$row["id"];$busName=$row["businessName"];   


 $upload_path = ''.$busName.'/productServiceImage/';

 $valid_formats = array("jpg", "png", "jpeg", "JPG", "PNG", "JPEG");
 if(isset($_POST) and $_SERVER['REQUEST_METHOD'] == "POST");
 {
 $name = $_FILES['pro_serImage']['name'];
  $size = $_FILES['pro_serImage']['size'];

 if(strlen($name))
 {
 list($txt, $ext) = explode(".", $name);
 if(in_array($ext, $valid_formats))
 {
 if($size<(1024*1024)) // Image size max 1 MB
{
$actual_image_name = time().$s.$busID.".".$ext;

$tmp = $_FILES['pro_serImage']['tmp_name'];
if(move_uploaded_file($tmp, $upload_path.$actual_image_name))
{
 list($width, $height) = getimagesize(''.$upload_path.$actual_image_name.'');

mysql_query("UPDATE product_service SET image='$actual_image_name',  
image_width='$width', image_height='$height' WHERE businessEmail='$login_bus' LIMIT  
1")or die ("Sorry we have a mysql error!");

echo "<img src='/".$upload_path.$actual_image_name."'>";
}
else
echo "failed! ".error_get_last()."";
}
else
echo "Image file size max 1 MB!"; 
}
else
echo "Invalid file format!"; 
}
else
echo "Please select image!";
exit;
}
?>

Answer 1

更改此行

echo "failed! ".error_get_last()."";

到

print_r(error_get_last());

Answer 2

如果您回显数组，它将显示“数组”。如果您发出问题，我不会这样做，但您应该使用print_r（）的var_dump（）而不是echo。这些将显示数组的内容。

这个数组有什么问题，只得到错误信息'array'

2 个答案: