这是我的代码,我可以打印每一行但是当出现空行时会打印出来;由于CSV文件格式,所以我想在空行出现时跳过
import csv
import time
ifile = open ("C:\Users\BKA4ABT\Desktop\Test_Specification\RDBI.csv", "rb")
for line in csv.reader(ifile):
if not line:
empty_lines += 1
continue
print line
答案 0 :(得分:9)
如果要跳过所有空白行,则应使用此测试:' '.isspace()
。
由于您可能想要做一些比将非空行打印到控制台更复杂的事情(不需要使用CSV模块),这里有一个涉及DictReader的示例:
#!/usr/bin/env python
# Tested with Python 2.7
# I prefer this style of importing - hides the csv module
# in case you do from this_file.py import * inside of __init__.py
import csv as _csv
# Real comments are more complicated ...
def is_comment(line):
return line.startswith('#')
# Kind of sily wrapper
def is_whitespace(line):
return line.isspace()
def iter_filtered(in_file, *filters):
for line in in_file:
if not any(fltr(line) for fltr in filters):
yield line
# A dis-advantage of this approach is that it requires storing rows in RAM
# However, the largest CSV files I worked with were all under 100 Mb
def read_and_filter_csv(csv_path, *filters):
with open(csv_path, 'rb') as fin:
iter_clean_lines = iter_filtered(fin, *filters)
reader = _csv.DictReader(iter_clean_lines, delimiter=';')
return [row for row in reader]
# Stores all processed lines in RAM
def main_v1(csv_path):
for row in read_and_filter_csv(csv_path, is_comment, is_whitespace):
print(row) # Or do something else with it
# Simpler, less refactored version, does not use with
def main_v2(csv_path):
try:
fin = open(csv_path, 'rb')
reader = _csv.DictReader((line for line in fin if not
line.startswith('#') and not line.isspace()),
delimiter=';')
for row in reader:
print(row) # Or do something else with it
finally:
fin.close()
if __name__ == '__main__':
csv_path = "C:\Users\BKA4ABT\Desktop\Test_Specification\RDBI.csv"
main_v1(csv_path)
print('\n'*3)
main_v2(csv_path)
答案 1 :(得分:7)
而不是
if not line:
这应该有效:
if not ''.join(line).strip():
答案 2 :(得分:1)
您可以去除前导和尾随空格,如果长度为零,则该行为空。
答案 3 :(得分:1)
import csv
with open('userlist.csv') as f:
reader = csv.reader(f)
user_header = next(reader) # Add this line if there the header is
user_list = [] # Create a new user list for input
for row in reader:
if any(row): # Pick up the non-blank row of list
print (row) # Just for verification
user_list.append(row) # Compose all the rest data into the list
答案 4 :(得分:0)
import csv
ifile=csv.reader(open('C:\Users\BKA4ABT\Desktop\Test_Specification\RDBI.csv', 'rb'),delimiter=';')
for line in ifile:
if set(line).pop()=='':
pass
else:
for cell_value in line:
print cell_value
答案 5 :(得分:0)
我的建议是只使用可以将文件分隔成行的csv阅读器。像这样,您可以检查行是否为空,如果是,则继续。
import csv
with open('some.csv', 'r') as csvfile:
# the delimiter depends on how your CSV seperates values
csvReader = csv.reader(csvfile, delimiter = '\t')
for row in csvReader:
# check if row is empty
if not (row):
continue
答案 6 :(得分:0)
此示例只是在跳过空行时以数组形式打印数据:
import csv
file = open("data.csv", "r")
data = csv.reader(file)
for line in data:
if line: print line
file.close()
我发现它比其他提供的例子更清晰。
答案 7 :(得分:0)
您始终可以检查逗号分隔值的数量。它似乎更有生产力和效率。
当迭代读取行时,由于这些是逗号分隔值的列表,因此您将获得一个列表对象。因此,如果没有元素(空白链接),那么我们可以使其跳过。
with open(filename) as csv_file:
csv_reader = csv.reader(csv_file, delimiter=",")
for row in csv_reader:
if len(row) == 0:
continue