Question

以下是我的查询以生成透视结果：

SELECT '# of Corrective Actions open and overdue' as [Corrective Actions breakdown], 
[405],
[2865],
[3142],
[405]+[2865]+[3142] as [Total]
FROM
(Select il.Locationid , ca.CorrectiveActionsid, il.locOrder, ca.isDeleted caDeleted, i.isDeleted iDeleted, i.CompanyId companyid,ca.CADateBy, ca.Status  from IncidentLocation il inner join incident i on il.IncidentId = i.IncidentId 
inner join CorrectiveActions ca on i.IncidentId = ca.IncidentId  
) AS SourceTable
PIVOT
(
COUNT(CorrectiveActionsid)
FOR LocationId IN ([405],[2865],[3142])
) PivotTable 

where locOrder = 0 and caDeleted =0 and iDeleted = 0 and companyId = 210
and CADateBy <= '2013-01-01'  and [Status] = 'Open'

我在考虑空白数据，计数应该返回o。但我一点也没有结果。请指导我做错了什么，我该怎么办才能得到零而不是空白所有计算值。

Answer 1

看起来你的查询没有返回任何行，你可以像这样修复它（我没有修复查询的其他部分，只是想给你一个解决方法）：

select
    A.[Corrective Actions breakdown],
    coalesce([405], 0) as [405],
    coalesce([2865], 0) as [2865],
    coalesce([3142], 0) as [3142],
    coalesce([405], 0) + coalesce([2865], 0) + coalesce([3142], 0) as [Total]
from (select '# of Corrective Actions open and overdue' as [Corrective Actions breakdown]) as A
    outer apply (
   SELECT
        [405],
        [2865],
        [3142]
   FROM
        (Select il.Locationid , ISNULL(ca.CorrectiveActionsid, 0) AS CorrectiveActionsid, il.locOrder, ca.isDeleted caDeleted, i.isDeleted iDeleted, i.CompanyId companyid,ca.CADateBy, ca.Status  from IncidentLocation il inner join incident i on il.IncidentId = i.IncidentId 
        inner join CorrectiveActions ca on i.IncidentId = ca.IncidentId  
        ) AS SourceTable
   PIVOT
        (
        COUNT(CorrectiveActionsid)
        FOR LocationId IN ([405],[2865],[3142])
        ) PivotTable 
        where locOrder = 0 and caDeleted =0 and iDeleted = 0 and companyId = 210
    and CADateBy <= '2013-01-01'  and [Status] = 'Open'
    ) as p

Answer 2

我希望count()返回0.如果不是，您可以尝试使用coalesce()：

coalesce([405], 0) as [405]

Answer 3

在SQL Server中，COUNT将忽略NULL值。话虽这么说，在要聚合的列上使用ISNULL函数。

   SELECT '# of Corrective Actions open and overdue' as [Corrective Actions breakdown], 
        [405],
        [2865],
        [3142],
        [405]+[2865]+[3142] as [Total]
   FROM
        (Select il.Locationid , ISNULL(ca.CorrectiveActionsid, 0) AS CorrectiveActionsid, il.locOrder, ca.isDeleted caDeleted, i.isDeleted iDeleted, i.CompanyId companyid,ca.CADateBy, ca.Status  from IncidentLocation il inner join incident i on il.IncidentId = i.IncidentId 
        inner join CorrectiveActions ca on i.IncidentId = ca.IncidentId  
        ) AS SourceTable
   PIVOT
        (
        COUNT(CorrectiveActionsid)
        FOR LocationId IN ([405],[2865],[3142])
        ) PivotTable 

   where locOrder = 0 and caDeleted =0 and iDeleted = 0 and companyId = 210
        and CADateBy <= '2013-01-01'  and [Status] = 'Open'

空数据的SQL数据透视表

3 个答案: