Question

在此处开发我的第一个应用程序，并使用基于类的视图(django.views.generic.base.View）来处理来自网页的请求。

在网页上，我有不同的表单发送POST请求，例如，有文本发布表单，评论表单，投票按钮等。我正在检查POST.has_key()以查看已发布和处理的表单根据那个。

什么是更好的方法呢？是否可以定义方法名称，如post_text，post_comment等，并配置dispatch（）以相应地运行方法？

Answer 1

我会这样做：

class AwesomeView(View):
    def post(self, request, *args, **kwargs):
        # This code is basically the same as in dispatch
        # only not overriding dispatch ensures the request method check stays in place.

        # Implement something here that works out the name of the 
        # method to call, without the post_ prefix
        # or returns a default method name when key is not found.
        # For example: key = self.request.POST.get('form_name', 'invalid_request')
        # In this example, I expect that value to be in the 'key' variable

        handler = getattr(
                           self,  # Lookup the function in this class
                           "post_{0}".format(key),  # Method name
                           self.post_operation_not_supported  # Error response method
                         )
        return handler(request, *args, **kwargs)

    def post_comment(self, request, *args, **kwargs):
        return HttpResponse("OK")  # Just an example response

在单个基于类的视图中处理不同POST请求的最佳方法？

1 个答案: