Question

如何获取资源文件夹中drawables的路径名？我试图在我的资源文件夹中获取图像并将其传递给函数进行解码。

路径“android.resource：//com.myapp.example/”+ R.drawable.image“没有用。

 Bitmap bitmap;

 File image = new File("android.resource://com.myapp.example/"+ R.drawable.image);

 bitmap.decodeFile(image);


public Bitmap decodeFile(File f) {
    try {
        // decode image size
        BitmapFactory.Options o = new BitmapFactory.Options();
        o.inJustDecodeBounds = true;
        BitmapFactory.decodeStream(new FileInputStream(f), null, o);
        // Find the correct scale value. It should be the power of 2.
        final int REQUIRED_SIZE = 70;
        int width_tmp = o.outWidth, height_tmp = o.outHeight;
        int scale = 1;
        while (true) {
            if (width_tmp / 2 < REQUIRED_SIZE
                    || height_tmp / 2 < REQUIRED_SIZE)
                break;
            width_tmp /= 2;
            height_tmp /= 2;
            scale++;
        }

        // decode with inSampleSize
        BitmapFactory.Options o2 = new BitmapFactory.Options();
        o2.inSampleSize = scale;
        return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
    } catch (FileNotFoundException e) {
    }
    return null;
}

Answer 1

BitmapFactory具有解码资源的功能：

Bitmap BitmapFactory.decodeResource (Resources res, int id, BitmapFactory.Options opts)

示例：

bitmap.decodeFile(R.drawable.image);

public Bitmap decodeFile(int resId) {
    try {
        // decode image size
        BitmapFactory.Options o = new BitmapFactory.Options();
        o.inJustDecodeBounds = true;
        BitmapFactory.decodeResource(getContext().getResources(), resId, o);
        // Find the correct scale value. It should be the power of 2.
        final int REQUIRED_SIZE = 70;
        int width_tmp = o.outWidth, height_tmp = o.outHeight;
        int scale = 1;
        while (true) {
            if (width_tmp / 2 < REQUIRED_SIZE
                    || height_tmp / 2 < REQUIRED_SIZE)
                break;
            width_tmp /= 2;
            height_tmp /= 2;
            scale++;
        }

        // decode with inSampleSize
        BitmapFactory.Options o2 = new BitmapFactory.Options();
        o2.inSampleSize = scale;
        return BitmapFactory.decodeResource(getContext().getResources(), resId, o2);
    } catch (Exception e) {
    }
    return null;
}

Answer 2

不，您无法获取路径，因为资源文件夹已编译到apk中，但您可以像这样获取资源：

Resources rsrc= getResources();
Drawable drawable= rsrc.getDrawable(R.drawable.datImage);
Bitmap bm = BitmapFactory.decodeResource(rsrc,drawable, opts);

android如何获取drawable的路径名

2 个答案: