Question

我正在使用此代码对用户进行排名：

    SELECT @rn:=@rn+1 AS rank, userid, amount
FROM (
  SELECT userid, sum(amount) AS amount
  FROM leads WHERE date(time)='2013-09-15'
  GROUP BY userid
  ORDER BY amount DESC
) t1 , (SELECT @rn:=0) t2;

结果如下：

rank    userid  amount
1         11    1.15
2         10    1.15

即使用户拥有相同金额，也会不断添加排名，任何想法如何解决这个问题？是的，我已经搜索了谷歌和这里的stackoverflow，但我无法解决这个问题。

Answer 1

首先，你不需要子查询来做你想做的事。

以下是对金额的密集排名，通过引入另一个变量来记住总金额：

SELECT userid, sum(amount) AS amount,
       if(@amount = amount, @rn, @rn := @rn + 1) as ranking,
       @amount := amount
FROM leads cross join
     (select @rn := 0, @amount := -1) const
WHERE date(time) = '2013-09-15'
GROUP BY userid
ORDER BY amount DESC;

MySql排名用户

1 个答案: