我正在使用 spring 进行 Java 项目。因此我使用Jackson
库进行转换以获得JSON
格式。< / p>
我的 java 类将是,
public class ChatInteraction extends Interaction{
private int ticketId;
private String name;
private String interactionType ;
private LinkedList<InteractionInfo> interactions;
public ChatInteraction(Message response) {
super(response);
interactions = new LinkedList<InteractionInfo>();
}
public int getTicketId() {
return ticketId;
}
public void setTicketId(int ticketId) {
this.ticketId = ticketId;
System.out.println("Ticket Id for Interaction : "+this.ticketId);
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
System.out.println("Name for Interaction : "+this.name);
}
public LinkedList<InteractionInfo> getInteractions() {
return interactions;
}
public String getInteractionType() {
return interactionType;
}
public void setInteractionType(String interactionType) {
this.interactionType = interactionType;
}
public void addInteraction(InteractionInfo interaction) {
this.interactions.add(interaction);
}
public void accept(int proxyId,String intxnId,int ticketId){
RequestAccept reqAccept = RequestAccept.create();
reqAccept.setProxyClientId(proxyId);
reqAccept.setInteractionId(intxnId);
reqAccept.setTicketId(ticketId);
System.out.println("New Chat RequestAccept Request Object ::: "+reqAccept.toString());
try{
if(intxnProtocol.getState() == ChannelState.Opened){
Message response = intxnProtocol.request(reqAccept);
System.out.println("New Chat RequestAccept Response ::: "+response.toString());
if(response != null ){
if( response.messageId() == EventAck.ID){
System.out.println("Accept new chat success !");
//EventAccepted accept = (EventAccepted)response;
//return "New chat Interaction accepted";
}else if(response.messageId() == EventError.ID){
System.out.println("Accept new chat Failed !");
//return "New chat Interaction rejected";
}
}
}else{
System.out.println("RequestAccept failure due to Interaction protocol error !");
}
}catch(Exception acceptExcpetion){
acceptExcpetion.printStackTrace();
}
}
public void join(String sessionId, String subject) {
RequestJoin join = RequestJoin.create();
join.setMessageText(MessageText.create(""));
join.setQueueKey("Resources:"); //Add the chat-inbound-key in multimedia of the optional tab values of the softphone application in CME
join.setSessionId(sessionId);
join.setVisibility(Visibility.All);
join.setSubject(subject);
KeyValueCollection kvc = new KeyValueCollection();
join.setUserData(kvc);
System.out.println("Join Request Object ::: "+join.toString());
try {
if(basicProtocol != null && basicProtocol.getState() == ChannelState.Opened){
Message response = basicProtocol.request(join);
if(response != null){
System.out.println("RequestJoin response ::: "+response);
if (response.messageId() == EventSessionInfo.ID) {
System.out.println("Join Request success !");
}else{
System.out.println("Join Request Failed !");
}
}
}else{
System.out.println("BasicChat protocol Error !");
//return "BasicChat protocol Error !";
}
} catch (ProtocolException e) {
e.printStackTrace();
} catch (IllegalStateException e) {
e.printStackTrace();
}
}
}
我只需要以 JSON 格式获取此类的interactionType
和interactions
属性,例如
{"interactionType":"invite","interactions" : [{"xx":"XX","yy":"YY"},{"xx":"XX","yy":"YY"}]}
注意:
我不需要此类的其他属性。
交互属性也没有 SETTER 。而不是我有 addInteractions()方法。这是否会影响 JSON 转换的任何行为?
此外,我还有其他一些方法,例如接受(...),加入(...)。
我正在使用 jackson-all-1.9.0.jar
答案 0 :(得分:4)
您可以使用@JsonIgnore
注释不需要的字段 - 请参阅杰克逊的manual on annotations。使用您的代码就是这样:
public class ChatInteraction extends Interaction{
@JsonIgnore
private int ticketId;
@JsonIgnore
private String name;
private String interactionType ;
private LinkedList<InteractionInfo> interactions;
答案 1 :(得分:3)
您可以使用可在班级上使用的@JsonIgnoreProperties
注释来实现此目的。
来自JavaDoc:
可用于抑制序列化的注释 属性(在序列化期间),或忽略JSON的处理 属性读取(在反序列化期间)。
示例:
// to prevent specified fields from being serialized or deserialized
// (i.e. not include in JSON output; or being set even if they were included)
\@JsonIgnoreProperties({ "internalId", "secretKey" })
示例,在您的情况下:
@JsonIgnoreProperties({ "ticketId", "name" })
public class ChatInteraction extends Interaction{
....
}
答案 2 :(得分:2)
最后我得到了其他人在线程中的答案解决方案以及stackoverflow中的类似答案,
我在 fvu 建议的子类和超类中标记了不需要的字段中的@JsonIgnore
。
我在其他帖子中建议的 objectMapper 中使用了myObjectMapper.setVisibility(JsonMethod.FIELD, Visibility.ANY);
,
ObjectMapper mapp = new ObjectMapper();
mapp.setVisibility(JsonMethod.FIELD, Visibility.ANY);
try {
json = mapp.writeValueAsString(info);
info.clear();
System.out.println("Chat Info in JSON String is :::> "+json);
} catch (Exception e) {
e.printStackTrace();
}