使用cURL使用代码返回完整状态

时间:2013-09-18 15:47:03

标签: php curl

我在PHP中使用cURL发送JSON请求。在验证错误上,我正在点击的API将返回400错误。如果我使用Chrome扩展程序Postman,我会看到整个状态,其代码如下所示:http://i.imgur.com/QMi5vX9.png

但是当我使用cURL发布时,这是我从curl_getinfo收到的:

(
    [url] => https://**sensitive**/
    [content_type] => 
    [http_code] => 400
    [header_size] => 157
    [request_size] => 315
    [filetime] => -1
    [ssl_verify_result] => 0
    [redirect_count] => 0
    [total_time] => 0.929666
    [namelookup_time] => 0.000949
    [connect_time] => 0.201551
    [pretransfer_time] => 0.741269
    [size_upload] => 173
    [size_download] => 0
    [speed_download] => 0
    [speed_upload] => 186
    [download_content_length] => 0
    [upload_content_length] => 0
    [starttransfer_time] => 0.929631
    [redirect_time] => 0
    [certinfo] => Array
        (
        )

)

有没有办法从cURL获取整个状态消息?

1 个答案:

答案 0 :(得分:1)

您可以从标题中获取整个http_code。

$response = curl_exec($ch);
$header_size = curl_getinfo($ch, CURLINFO_HEADER_SIZE);
$headers = substr($response, 0, $header_size);