Question

我通过HttpClient从网站获得了此值。

[
    {
        "scout": "webdriver",
        "short_version": "4.3",
        "long_name": "iPad",
        "api_name": "ipad",
        "long_version": "4.3.",
        "automation_backend": "webdriver",
        "os": "Mac 10.4"
    },
    {
        "scout": "webdriver",
        "short_version": "5.0",
        "long_name": "Firefox",
        "api_name": "firefox",
        "long_version": "14",
        "automation_backend": "webdriver",
        "os": "Mac 10.5"
    },
    {
        "scout": "webdriver",
        "short_version": "4",
        "long_name": "Firefox",
        "api_name": "firefox",
        "long_version": "15",
        "automation_backend": "webdriver",
        "os": "Mac 10.6"
    },
    {
        "scout": "webdriver",
        "short_version": "5",
        "long_name": "Chrome",
        "api_name": "chrome",
        "long_version": "5.0.1.",
        "automation_backend": "webdriver",
        "os": "Mac 10.7"
    }
]

我希望将此数据转换为以下格式：

[OS: {Mac10.4,Mac10.5}]

等，OS列表

和

[{api_name: {firefox:{14,15}} }]

等，浏览器列表及其版本。

列表太长了OS和浏览器。如何使用json或任何其他方法解析它？

Answer 1

我建议你看看json-smart库。它重量轻，速度快。（https://code.google.com/p/json-smart/）

然后你可以写这样的东西（只是例子）：

    Map<String, List<String>> osMap = new HashMap<String, List<String>>();
    osMap.put("OS", new ArrayList<String>());

    Map<String, Map<String, List<String>>> apiNameMap = 
        new HashMap<String, Map<String, List<String>>>();
    apiNameMap.put("api_name", new HashMap<String, List<String>>());

    JSONArray ja = (JSONArray) JSONValue.parse(JSON_STRING);
    for (Object obj : ja) {
        JSONObject jsonObj = (JSONObject) obj;
        String os = (String) jsonObj.get("os");
        String apiName = (String) jsonObj.get("api_name");
        String longVersion = (String) jsonObj.get("long_version");

        // OS
        if (!osMap.get("OS").contains(os)) {
            osMap.get("OS").add(os);
        }

        // API
        if (!apiNameMap.get("api_name").containsKey(apiName)) {
            apiNameMap.get("api_name")
                    .put(apiName, new ArrayList<String>());
        }
        apiNameMap.get("api_name").get(apiName).add(longVersion);

    }

    System.out.println(JSONValue.toJSONString(osMap));
    System.out.println(JSONValue.toJSONString(apiNameMap));

Answer 2

这样做：

$(document).ready(function(){
//here getting the json Array from session
    var d  = json1;
    //after making a variable array to put j son data one by one by looping
    var availableTags = new Array();
    for(var i=0;i<d.forms.length;i++){
        availableTags[i] = d.forms[i].productName;
    }
});

如何将给定的字符串解析为有意义的json？

2 个答案: