我创建了一个php日历,一次显示一周。这是我创建的代码
<?php
$week = date("W");
$year = (isset($_GET['year']))?$_GET['year']:date("Y");
$week = (isset($_GET['week']))?$_GET['week']:Date('W');
if($week>53){
$year+= 1;
$week=1;
}
?>
<a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week+1).'&year='.$year; ?>">Next Week</a> <!--Next week-->
<a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week-1).'&year='.$year; ?>">Pre Week</a> <!--Previous week-->
<table border="1px">
<tr>
<td>Employee</td>
<?php
for($day=1; $day<=7; $day++)
{
$d = strtotime($year."W".$week.$day);
echo "<td>".date('l',$d )."<br>";
echo date('d M',$d)."</td>";
}
?>
</tr>
当我试图去下周时,它正常工作。但是,当这一年正在发生变化时,它将在明年不起作用。
答案 0 :(得分:12)
将周计算保留为DateTime::setIsoDate()方法。
以下是针对您的问题的最简单和最佳解决方案:
<?php
$dt = new DateTime;
if (isset($_GET['year']) && isset($_GET['week'])) {
$dt->setISODate($_GET['year'], $_GET['week']);
} else {
$dt->setISODate($dt->format('o'), $dt->format('W'));
}
$year = $dt->format('o');
$week = $dt->format('W');
?>
<a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week-1).'&year='.$year; ?>">Pre Week</a> <!--Previous week-->
<a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week+1).'&year='.$year; ?>">Next Week</a> <!--Next week-->
<table>
<tr>
<td>Employee</td>
<?php
do {
echo "<td>" . $dt->format('l') . "<br>" . $dt->format('d M Y') . "</td>\n";
$dt->modify('+1 day');
} while ($week == $dt->format('W'));
?>
</tr>
</table>
答案 1 :(得分:2)
当您使用strtotime
时,您的周必须两位数。如果在for
循环之前周低于10,则必须前置零。
if($week < 10) {
$week = '0'. $week;
}
for($day = 1; $day <= 7; $day++) {
另外,一年只有52周,开始的条件应该是。
if($week > 52) {
$year++;
$week = 1;
} elseif($week < 1) { // If you want the possibility to go back too
$year--;
$week = 52;
}
完整代码:
<?php
$year = (isset($_GET['year'])) ? $_GET['year'] : date("Y");
$week = (isset($_GET['week'])) ? $_GET['week'] : date('W');
if($week > 52) {
$year++;
$week = 1;
} elseif($week < 1) {
$year--;
$week = 52;
}
?>
<a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week == 52 ? 1 : 1 + $week).'&year='.($week == 52 ? 1 + $year : $year); ?>">Next Week</a> <!--Next week-->
<a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week == 1 ? 52 : $week -1).'&year='.($week == 1 ? $year - 1 : $year); ?>">Pre Week</a> <!--Previous week-->
<table border="1px">
<tr>
<td>Employee</td>
<?php
if($week < 10) {
$week = '0'. $week;
}
for($day= 1; $day <= 7; $day++) {
$d = strtotime($year ."W". $week . $day);
echo "<td>". date('l', $d) ."<br>". date('d M', $d) ."</td>";
}
?>
</tr>
</table>