我有一个HTML代码
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js"></script>
<script>
$( document ).ready(function() {
$("#username").keyup(function(){
var username = $("#username").val().trim();
if(username=="")
{
$("#usernameerrortext").html("Username should not be empty");
return false;
}
else if(/[!@#$%\\^&*(){}[\]<>?\/|\-]/.test(username))
{
$("#usernameerrortext").html("Username should not contain special charatcers");
return false;
}
else
{
$("#usernameerrortext").html("");
return true;
}
});
$("#password").keyup(function(){
var password = $("#password").val().trim();
if(password=="")
{
$("#passworderrortext").html("Password should not be empty");
return false;
}
else
{
$("#passworderrortext").html("");
return true;
}
});
});
</script>
<br/>Username:<input type="text" name="username" id="username"/>
<font color="red"><div id="usernameerrortext"></div></font>
<br>
Password:<input type="password" name="password" id="password"/>
<font color="red"><div id="passworderrortext"></div></font>
这完全可以作为html页面使用。但是,当我将此代码粘贴到如下所示的JSP文件中时,我的jquery无效,
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>HDB SBBS</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js"></script>
<script>
$( document ).ready(function() {
$("#username").keyup(function(){
var username = $("#username").val().trim();
if(username=="")
{
$("#usernameerrortext").html("Username should not be empty");
return false;
}
else if(/[!@#$%\\^&*(){}[\]<>?\/|\-]/.test(username))
{
$("#usernameerrortext").html("Username should not contain special charatcers");
return false;
}
else
{
$("#usernameerrortext").html("");
return true;
}
});
$("#password").keyup(function(){
var password = $("#password").val().trim();
if(password=="")
{
$("#passworderrortext").html("Password should not be empty");
return false;
}
else
{
$("#passworderrortext").html("");
return true;
}
});
});
</script>
</head>
<body>
<center>
<h2>Login</h2>
<form name="loginForm" id="loginForm" action="LoginServlet" method="post">
<br/>Username:<input type="text" name="username" id="username">
<font color="red"><div id="usernameerrortext"></div></font>
<br/>Password:<input type="password" name="password" id="password">
<font color="red"><div id="passworderrortext"></div></font>
<br/><input type="submit" value="Submit">
</form>
</center>
</body>
</html>
这里需要帮助。
答案 0 :(得分:0)
这是更新的Jquery代码:
$(document).ready(function() {
$("#username").on('focusout',function(){
var username = $("#username").val().trim();
if(username==="")
{
$("#usernameerrortext").html("Username should not be empty");
return false;
}
else if(/[!@#$%\\^&*(){}[\]<>?\/|\-]/.test(username))
{
$("#usernameerrortext").html("Username should not contain special charatcers");
return false;
}
else
{
$("#usernameerrortext").html("");
return true;
}
});
$("#password").on('focusout',function(){
var password = $("#password").val().trim();
if(password==="")
{
$("#passworderrortext").html("Password should not be empty");
return false;
}
else
{
$("#passworderrortext").html("");
return true;
}
});
});
我为你创建了一个演示小提琴,FIDDLE
您需要在要运行此脚本的页面的head标记中包含jquery lib。
因为没有什么必须做,只需在头标记<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js">