Question

我已经完成了Scrollview（8images）+工具栏的代码。当我尝试单击工具栏按钮项时，滚动视图不会按预期返回。下面是代码。

当我点击工具栏按钮时，没有触发“IBAction clickprjinfo”的操作，我已通过连接检查器中的Barbuttonitem确认已对此IBACTION执行了“SentAction”。

在运行期间，当我点击按住工具栏按钮+触摸scroolview屏幕+然后释放按钮，然后它会触发IBACTION。

任何人都有助于通知我的错误或更好的理解方法。

-(void)viewDidLoad
{
   [super viewDidLoad];
   [self pgcontrolview];
}

-(void) pgcontrolview  {
   pageC.numberOfPages=8;
   pageC.currentPage=0;
   for (int i=1; i<=8; i++)
   {
       UIImageView *images=[[UIImageView alloc]initWithImage:[UIImage imageNamed:[NSString stringWithFormat:@"%d.jpg",i]]];
       images.frame=CGRectMake((i-1)*1024, 0, 1024, 760);
       [scroller addSubview:images];
   }
   scroller.delegate=self;
   scroller.contentSize=CGSizeMake(1024*8, 760);
   scroller.pagingEnabled=YES;

   UITapGestureRecognizer *tap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handle_Tap:)];
   tap.numberOfTapsRequired = 1;
   tap.numberOfTouchesRequired = 1;
   [self.view addGestureRecognizer:tap];
}

-(IBAction)clickprjinfo:(id)sender{
   pageC.currentPage=1;
   CGRect frame=scroller.frame;
   frame.origin.x=0;//frame.size.width*page;
   frame.origin.y=0;
   [scroller scrollRectToVisible:frame animated:YES];
}

Answer 1

添加Gesture委托方法如下

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
// test if our control subview is on-screen
if ([touch.view isKindOfClass:[UIControl class]]) {
    // we touched a button, slider, or other UIControl
    return NO; // ignore the touch
}
return YES; // handle the touch
}

因为它考虑将UIButton点击为UITapGesture，所以你不需要在UIButton上允许UITapGesture作为上面的委托方法忽略UIControl上的触摸（反过来UIButton）允许执行

-(IBAction)clickprjinfo:(id)sender行动

IOS工具栏按钮项不会触发滚动条的操作

1 个答案: