在JOB SCHEDULER的job_action中我有以下SQL
'BEGIN
ALTER TRIGGER AFTERIUDSETTLEMENTS DISABLE;
ALTER TRIGGER AFTERIUDLIQUIDATIONSDETAILS DISABLE;
UPDATE APPOINTSOFCAS A SET INLD = (SELECT COUNT(*) FROM LIQUIDATIONSDETAILS LD WHERE A.CUSTOMERID = LD.CUSTOMERID AND A.ID = LD.APPOINTOFCAID AND A.KINDCONTROLID = LD.KINDCONTROLID);
UPDATE APPOINTSOFCAS A SET INSD = (SELECT COUNT(*) FROM SETTLEMENTS S WHERE A.CUSTOMERID = S.CUSTOMERID AND A.ID = S.APPOINTOFCAID AND A.KINDCONTROLID = S.KINDCONTROLID);
COMMIT;
ALTER TRIGGER AFTERIUDSETTLEMENTS ENABLE;
ALTER TRIGGER AFTERIUDLIQUIDATIONSDETAILS ENABLE;
END;'
但在运行后,作业失败并出现以下错误:
ORA-06550: γραμμή 2, στήλη 29:
PLS-00103:遇到以下任何一种情况时遇到符号“ALTER”:
begin case declare exit for goto if loop mod null pragma raise return select update while with <an identifier>
<a double-quoted delimited-identifier> <a bind variable> <<
συνέχεια close current delete fetch lock insert open
rollback savepoint set sql execute commit forall merge pipe
οριστική διαγραφή
可以在JOB SCHEDULER中禁用或启用触发器吗?
答案 0 :(得分:2)
ALTER语句是DDL,这意味着在不使用EXECUTE IMMEDIATE的情况下无法在PL / SQL块的范围内完成。
这是相当不寻常的,这意味着您的触发器会在每个会话中被禁用,因此如果发生其他任何事情,它们将不会触发任何更改。这是可能的,但这感觉不对。
您也可以在一个语句中进行两次更新,效率更高。
begin
execute immediate 'alter trigger afteriudsettlements disable';
execute immediate 'alter trigger afteriudliquidationsdetails disable';
update appointsofcas a
set inld = ( select count(*)
from liquidationsdetails ld
where a.customerid = ld.customerid
and a.id = ld.appointofcaid
and a.kindcontrolid = ld.kindcontrolid )
, insd = ( select count(*)
from settlements s
where a.customerid = s.customerid
and a.id = s.appointofcaid
and a.kindcontrolid = s.kindcontrolid );
commit;
execute immediate 'alter trigger afteriudsettlements enable';
execute immediate 'alter trigger afteriudliquidationsdetails enable';
end;
/