在Android上,我正在尝试使用Google Drive API上传Cordova / Phonegap getPicture()的输出:插入文件。有没有办法使用FILE_URI而不是DATA_URL(base64)?
我首先尝试了Camera.DestinationType.DATA_URL,但它没有像预期的那样返回Base64数据,它只返回与FILE_URI相同的东西。所以现在我想弄清楚如何将FILE_URI传递给Google Drive Insert File(需要Base64)。有没有办法将FILE_URI转换为Base64?
科尔多瓦代码:
navigator.camera.getPicture(onSuccess, onFail,
{ quality: 50, destinationType: Camera.DestinationType.FILE_URI });
function onSuccess(imageURI) {
var image = document.getElementById('myImage');
image.src = imageURI;
// need to do something like this:
var fileData = ConvertToBase64(imageURI);
insertFile(fileData);
}
Google云端硬盘代码:
/**
* Insert new file.
*
* @param {File} fileData File object to read data from.
* @param {Function} callback Function to call when the request is complete.
*/
function insertFile(fileData, callback) {
const boundary = '-------314159265358979323846';
const delimiter = "\r\n--" + boundary + "\r\n";
const close_delim = "\r\n--" + boundary + "--";
var reader = new FileReader();
reader.readAsBinaryString(fileData);
reader.onload = function(e) {
var contentType = fileData.type || 'application/octet-stream';
var metadata = {
'title': fileData.fileName,
'mimeType': contentType
};
var base64Data = btoa(reader.result);
var multipartRequestBody =
delimiter +
'Content-Type: application/json\r\n\r\n' +
JSON.stringify(metadata) +
delimiter +
'Content-Type: ' + contentType + '\r\n' +
'Content-Transfer-Encoding: base64\r\n' +
'\r\n' +
base64Data +
close_delim;
var request = gapi.client.request({
'path': '/upload/drive/v2/files',
'method': 'POST',
'params': {'uploadType': 'multipart'},
'headers': {
'Content-Type': 'multipart/mixed; boundary="' + boundary + '"'
},
'body': multipartRequestBody});
if (!callback) {
callback = function(file) {
console.log(file)
};
}
request.execute(callback);
}
}
答案 0 :(得分:3)
我意识到这有点旧 - 但现在看起来你可以在phoneGap中使用FileReader
。
我还没有对此进行过测试,但喜欢这样的东西也可以使用,没有画布黑客。
[编辑 - 测试并修改了以下代码。适合我:D]
var cfn = function(x) { console.log(x) };
var cameraOps = { quality: 50, destinationType: Camera.DestinationType.FILE_URI };
navigator.camera.getPicture(function(imagePath) {
window.resolveLocalFileSystemURL(imagePath, function(fileEntry) {
fileEntry.file(function (file) {
var reader = new FileReader();
reader.onloadend = function(evt) {
console.log("read success!!!");
console.log(evt.target.result);
};
reader.readAsDataURL(file);
}, cfn);
}, cfn);
}, cfn);
答案 1 :(得分:2)
是你可以......
将Destination Type
指定为FILE_URI
本身,在imagedata中,您将获取图像文件,将其放置在图像标记中,然后将其放在HTML5 canvas
内,并且canvas有一个名为<的方法strong> toDataURL ,您可以在其中获取相应图像的base64。
function onSuccess(imageData)
{
var $img = $('<img/>');
$img.attr('src', imageData);
$img.css({position: 'absolute', left: '0px', top: '-999999em', maxWidth: 'none', width: 'auto', height: 'auto'});
$img.bind('load', function()
{
var canvas = document.createElement("canvas");
canvas.width = $img.width();
canvas.height = $img.height();
var ctx = canvas.getContext('2d');
ctx.drawImage($img[0], 0, 0);
var dataUri = canvas.toDataURL('image/png');
});
$img.bind('error', function()
{
console.log('Couldnt convert photo to data URI');
});
}
答案 2 :(得分:2)
感谢Arun指出我正确的方向。我最终使用了这个基于http://jsfiddle.net/jasdeepkhalsa/L5HmW/
的javascript函数function getBase64Image(imgElem) {
// imgElem must be on the same server otherwise a cross-origin error will be thrown "SECURITY_ERR: DOM Exception 18"
var canvas = document.createElement("canvas");
canvas.width = imgElem.clientWidth;
canvas.height = imgElem.clientHeight;
var ctx = canvas.getContext("2d");
ctx.drawImage(imgElem, 0, 0);
var dataURL = canvas.toDataURL("image/jpeg");
dataURL = dataURL.replace(/^data:image\/(png|jpg|jpeg);base64,/, "");
return dataURL;
}