Question

我需要在div中加载外部内容。我发现了一个代码来执行此操作，但我的脚本不再起作用了。有人可以帮忙吗？我是这类工作的新手。

由于

function ajaxFunction(id, url){
    var xmlHttp;
    try {// Firefox, Opera 8.0+, Safari
        xmlHttp = new XMLHttpRequest();     
    } catch (e) {// Internet Explorer
        try {
            xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");
        } catch (e) {
            try {
                xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
            } catch (e) {
                alert("Your browser does not support AJAX!");
                return false;
            }
        }
    }

    xmlHttp.onreadystatechange = function(){
        if (xmlHttp.readyState == 4) {
            //Get the response from the server and extract the section that comes in the body section of the second html page avoid inserting the header part of the second page in your first page's element
            var respText = xmlHttp.responseText.split('<body>');
            elem.innerHTML = respText[1].split('</body>')[0];
        }
    }

    var elem = document.getElementById(id);
    if (!elem) {
        alert('The element with the passed ID doesn\'t exists in your page');
        return;
    }

    xmlHttp.open("GET", url, true);
    xmlHttp.send(null);

}

编辑 - 这是我的HTML代码。这是我称之为ajax。

<div id="right" class="anim">
    <div class="exit">
    <a class="btnclose"><span class="glyphicon glyphicon-remove"></span></a>
    </div>
    <div class="portfolio-box" id="git-box"></div>
    </div>
<div class="container">
        <div id="centerContainer" class="col-lg-12">
            <div id="grid">

                <div class="box" data-category="Branding" data-move="right">                    
                    <div class="hide" data-thumbnail="images/portfolio/branding/git.jpg"> </div>
                    <a type="link" value="Call Project" id="project-link" onclick="ajaxFunction('git-box','portfolio/git.html')">
                    <div class="thumbnail-caption">
                        <h3>Groupe<br> intégration<br> Travail</h3>
                        <h5>Branding</h5>
                    </div></a>
                </div>

编辑 - 这是必须在AJAX插入的div中激活的代码

(function () {
    var $frame = $('#centered');
    var $wrap  = $frame.parent();

    // Call Sly on frame
    $frame.sly({
        horizontal: 1,
        itemNav: 'centered',
        smart: 1,
        activateOn: 'click',
        mouseDragging: 1,
        touchDragging: 1,
        releaseSwing: 1,
        startAt: 1,
        scrollBar: $wrap.find('.scrollbar'),
        scrollBy: 1,
        speed: 300,
        elasticBounds: 1,
        easing: 'easeOutExpo',
        dragHandle: 1,
        dynamicHandle: 1,
        clickBar: 1,

        // Buttons
        prev: $wrap.find('.prev'),
        next: $wrap.find('.next')
    });

    $(window).resize(function(e) {

    $frame.sly('reload');
    });

}());

});

Answer 1

将要应用的整个js放在函数中加载ajax的内容中：

function loadSly() {
    var $frame = $('#centered');
    var $wrap  = $frame.parent();

    // Call Sly on frame
    $frame.sly({
        horizontal: 1,
        itemNav: 'centered',
        smart: 1,
        activateOn: 'click',
        mouseDragging: 1,
        touchDragging: 1,
        releaseSwing: 1,
        startAt: 1,
        scrollBar: $wrap.find('.scrollbar'),
        scrollBy: 1,
        speed: 300,
        elasticBounds: 1,
        easing: 'easeOutExpo',
        dragHandle: 1,
        dynamicHandle: 1,
        clickBar: 1,

        // Buttons
        prev: $wrap.find('.prev'),
        next: $wrap.find('.next')
    });

    $(window).resize(function(e) {
        $frame.sly('reload');
    });
}

然后在html插入后执行：

xmlHttp.onreadystatechange = function(){
    if (xmlHttp.readyState == 4) {
        //Get the response from the server and extract the section that comes in the body section of the second html page avoid inserting the header part of the second page in your first page's element
        var respText = xmlHttp.responseText.split('<body>');
        elem.innerHTML = respText[1].split('</body>')[0];
        // here you apply the javascript code to the html loaded
        loadSly();
    }
}

在AJAX加载的div上使用脚本

1 个答案: