Question

例如，如果我输入“python prog.py create filename”，结果应该是创建一个名为“filename”的文件。但我不知道如何将“args”放入创造的定义中。有人可以给我一些建议吗？这是代码：

    import argparse
    import sys

    class ExecuteShell(object):

        def create(self, args):

        """create a file"""
        print 'xxxxxxxxxxx', args 

            #return args 

        def list(self, args):

        """ccccccc"""
        print args

            #return args

        def delete(self, args):

        """ddddddd"""
        print 'ddddddd'

            #return args

    class TestShell(object):

       def _find_actions(self, subparsers, actions_module, args):

            for attr in (action for action in dir(actions_module) if not action.startswith('__')):

            callback = getattr(actions_module, attr)

            desc = callback.__doc__ or ''

                subparser = subparsers.add_parser(attr, description=desc, add_help=False)

                subparser.add_argument('-h', '--help', action='help',
                                       help=argparse.SUPPRESS)    
                .......

       def main(self, args):

            parser = argparse.ArgumentParser()

            subparsers = parser.add_subparsers()

            a = ExecuteShell()

            subcommand_parser = self._find_actions(subparsers, a, args)

            (options, args) = parser.parse_known_args(args)

    if __name__ == "__main__":

        a = TestShell()
        a.main(sys.argv[1:])

非常感谢！

Answer 1

在您概述的框架内，我可能会像以下程序一样实现它。关键项目是：

parser.add_subparsers采用dest参数。这可以让您知道调用了哪个subparser。
将一个项目添加到收集文件名的子分析器（subparser.add_argument('files',...)下面）
实际调用命令子例程（getattr(a,options.command) ...行）

import argparse
import sys

class ExecuteShell(object):
    # This function demonstrates that you can put 
    # methods in ExecuteShell(), if you need to, 
    # without having them appear as command-line commands
    # simply by prepending an underscore.
    def _useful(self):
        """Useful method that ISNT a command."""
        return 3.14159

    def create(self, args):
        """create a file"""
        print 'xxxxxxxxxxx', args 

    def list(self, args):
        """ccccccc"""
        print args

    def delete(self, args):
        """ddddddd"""
        print 'ddddddd'

class TestShell(object):

   def find_actions(self, subparsers, actions_module, args):
        for attr in (action for action in dir(actions_module) if not action.startswith('_')):
            callback = getattr(actions_module, attr)
            desc = callback.__doc__ or ''
            subparser = subparsers.add_parser(attr, description=desc, help=desc)

            # This add_argument describes the positional argument, like so:
            #   'files' -- the result of matching this argument will be
            #              stored in `options.files`
            #   metavar='FILE' -- The help messages will use the word "FILE"
            #                     when describing this argument
            #   nargs='+' -- `narg` describes how many arguments this should
            #                match. The value `+` means "all of them, but at
            #                least one." 
            subparser.add_argument('files', metavar='FILE', nargs='+')

   def main(self, args):
        # setup parser
        parser = argparse.ArgumentParser()
        subparsers = parser.add_subparsers(dest='command')
        a = ExecuteShell()
        subcommand_parser = self.find_actions(subparsers, a, args)

        # Run parser
        args = parser.parse_args(args)

        # Run selected command
        # If we reach this statement, then:
        #    args.command is the command the user chose, 
        #       for example, 'create' or 'list'
        #    args.files is the list of arguments that followed 'create' or 'list'
        #    a is an instance of ExecuteShell
        #    getattr(a, args.command) is the attribute or method of `a`
        #       the name in `args.command`, for example, a.create or a.list
        #    getattr(a, args.command)(args.files) invokes that method,
        #       passing in the list of user arguments
        #    So, this line in effect might call `a.create(['file1', 'file2'])`
        getattr(a, args.command)(args.files)

if __name__ == "__main__":

    a = TestShell()
    a.main(sys.argv[1:])

如何将'args'放入python中的argparse.Argument中

1 个答案: