Question

我正在尝试获取提交的总数，我想要2个结果，1个具有特定状态的提交，1个具有所有状态：

SELECT submissions.campid, 
       COUNT(submissions.id) AS subsCountTotal, 
       (SELECT COUNT(submissions.id)
        FROM submissions,campaings  
        WHERE submissions.campid = campaings.id 
        AND campaings.status = 1 
        and submissions.time  >= campaings.startdate 
        and submissions.status = 10
        GROUP BY submissions.campid) AS subsCountngood 
FROM submissions, campaings 
WHERE submissions.campid = campaings.id 
AND  campaings.status = 1
and CASE 
    WHEN campaings.enddate = '0000-00-00' THEN  submissions.time  >= campaings.startdate 
    ELSE  submissions.time <= campaings.enddate
END
GROUP BY submissions.campid `

任何帮助将不胜感激:) 谢谢。

Answer 1

查看此子查询

SELECT COUNT(submissions.id)  
FROM submissions,campaings 
WHERE submissions.campid = campaings.id AND  campaings.status = 1 and submissions.time  >= campaings.startdate and submissions.status = 10  
GROUP BY submissions.campid

分组时，您可能会获得多个群组，即多个群组。如何在一行中放置多个值。

Answer 2

您的CASE应该导致错误（或者这是MySQL特定的扩展名）？

恕我直言，你只需要：

SELECT submissions.campid, 
       COUNT(*) AS subsCountTotal, 
       SUM(CASE WHEN submissions.status = 10 THEN 1 ELSE 0 END) AS subsCountngood 
FROM submissions, campaings 
WHERE submissions.campid = campaings.id 
AND  campaings.status = 1
AND 
 (   submissions.time <= campaings.enddate 
  OR 
     (campaings.enddate = '0000-00-00' AND submissions.time  >= campaings.startdate)
 )
GROUP BY submissions.campid

Answer 3

SELECT submissions.campid, 
       COUNT(submissions.id) AS subsCountTotal, 
       (SELECT COUNT(submissions.id)
        FROM submissions,campaings  
        WHERE submissions.campid = outer_camp.id 
        AND campaings.status = 1 
        and submissions.time  >= outer_camp.startdate 
        and submissions.status = 10
        GROUP BY submissions.campid) AS subsCountngood 
FROM submissions outer_sub, campaings outer_camp
WHERE submissions.campid = campaings.id 
AND  campaings.status = 1
and CASE 
    WHEN campaings.enddate = '0000-00-00' THEN  submissions.time  >= campaings.startdate 
    ELSE  submissions.time <= campaings.enddate
END
GROUP BY submissions.campid

您需要关联子查询。

＃1242 - 子查询返回超过1行

3 个答案: