Question

您好我需要一个脚本，根据ID更新另一个表中的行，然后从第二个表中删除它复制的数据。

这是我的表

Documents
--------
DocumentID(PK)
RealFileName
FileName

ImageDocuments
--------------
ImageDocumentId(PK)
DocumentId(FK)
OriginalFileName
StorageFileName

两个表之间的映射是一对一的。

目前我有更新表的脚本，但我不知道如何从文档表中删除值。这是我到目前为止所做的：

UPDATE [dbo].[ImageDocuments]
SET [dbo].[ImageDocuments].[OriginalFileName] = d.FileName,
    [dbo].[ImageDocuments].[StorageFileName] = d.RealName
FROM [dbo].[ImageDocuments] as fu, 
     [dbo].[Documents] as d
WHERE fu.DocumentID = d.DocumentID

如何从文档表中删除添加到ImageDocuments表的行？

更新我创建了一个删除查询，任何人都可以验证这是否可行corectly：

DELETE [dbo].[Documents]
FROM [dbo].[ImageDocuments] as fu
INNER JOIN [dbo].[Documents] as d ON d.DocumentID = fu.DocumentID

Answer 1

使用此：

UPDATE [dbo].[ImageDocuments]
SET [dbo].[ImageDocuments].[OriginalFileName] = d.FileName,
    [dbo].[ImageDocuments].[StorageFileName] = d.RealName
OUTPUT INSERTED.ImageDocumentId
INTO @Ids
FROM [dbo].[ImageDocuments] as fu, 
     [dbo].[Documents] as d
WHERE fu.DocumentID = d.DocumentID;

DELETE FROM Documents
WHERE DocumentID IN (SELECT ImageDocumentId FROM @IDs);

Answer 2

我认为这应该有用。

由于您已经复制了ImageDocuments中的所有行，因此可以安全地删除文档中的所有DocumentID

    UPDATE [dbo].[ImageDocuments]
    SET [dbo].[ImageDocuments].[OriginalFileName] = d.FileName,
        [dbo].[ImageDocuments].[StorageFileName] = d.RealName
    FROM [dbo].[ImageDocuments] as fu, 
         [dbo].[Documents] as d
    WHERE fu.DocumentID = d.DocumentID;

    Delete From Documents where Documents.DocumentID in 
(Select ImageDocuments.DocumentID from ImageDocuments);

Answer 3

我会使用临时表来存储两个表中的匹配记录。然后，通过使用该临时表，您可以删除已在其他表中使用过的数据。

如;

DECLARE @Table TABLE (MatchingId INT)
INSERT INTO @Table 
SELECT DocumentID FROM [ImageDocuments] ImgDoc 
INNER JOIN [Documents] doc 
    ON ImgDoc.DocumentID = doc.DocumentID

UPDATE [dbo].[ImageDocuments]
SET [dbo].[ImageDocuments].[OriginalFileName] = d.FileName,
    [dbo].[ImageDocuments].[StorageFileName] = d.RealName
FROM [dbo].[ImageDocuments] as fu, 
     [dbo].[Documents] as d
WHERE fu.DocumentID = d.DocumentID

DELETE FROM DocumentID WHERE DocumentID IN 
(SELECT DocumentID FROM @Table )

如何将数据迁移到另一个表

3 个答案: