Question

我是c ++的新手，仍然试图用构造函数等来掌握类实现。

我有一个程序分为3个文件，一个头文件，一个类实现文件和驱动文件。

在头文件中，我得到一个错误“缺少显式类型（假定为'int'）这行代码的操作符＆lt;＆lt;（ostream＆amp;，ARRAY＆amp;）;

在我的类实现文件中，我收到此朋友函数的错误，说我无法访问私有成员。

在我的驱动程序文件中，我收到错误“无法确定哪个实例重载函数'endl'意图”用于此代码：cout＆lt;

我将留下下面的一些代码，首先是.h文件，然后是类实现文件，然后是驱动程序文件。非常感谢任何帮助清理它。

标题

#include <iostream>
#include <string>
#include <fstream>

using namespace std;

class ARRAY
{
public:

    ARRAY();

    ARRAY(int );

    ARRAY(const ARRAY &);
    ~ARRAY();

    friend operator<<(ostream &, ARRAY &);

private:

    string *DB;

    int count;

    int capacity;
};

实施档案

#include "array.h"

ARRAY::ARRAY()
{
    cout<<"Default Constructor has been called\n";

    count = 0;
    capacity = 2;

    DB = new string[capacity];
}

ARRAY::ARRAY(int no_of_cells)
{
    cout<<"Explicit-Value Constructor has been called\n";

    count = 0;
    capacity = no_of_cells;

    DB = new string[capacity];
}

ARRAY::ARRAY(const ARRAY & Original)
{
    cout<<"The copy constructor has been invoked\n";
    count = Original.count;
    capacity = Original.capacity;

    DB = new string[capacity];

    for(int i=0; i<count; i++)
    {
        DB[i] =Original.DB[i];
    }

}

inline ARRAY::~ARRAY()
{

    cout<<"Destructor Called\n";
    delete [ ] DB;
}

ostream & operator<<(ostream & out, ARRAY & Original)
{
    for(int i=0; i< Original.count; i++)
    {
        out<<"DB[" << i <<"] = "<< Original.DB[i]<<endl;
    }
    return out;
}

驱动程序文件

#include <iostream>
#include <string>
#include "array.h"
using namespace std;

int main()
{
    cout<<"invoking the default constructor (11)"<<endl;
    ARRAY myArray;
    cout<<"Output after default constructor called\n";
    cout<<myArray<<endl<<endl;

    cout<<"invoking the explicit-value constructor (12)"<<endl;
    ARRAY yourArray(5);
    cout<<"Output after explicit-value constructor called\n";
    //cout<<yourArray<<endl<<endl;


    cout<<"invoking the copy constructor (3)"<<endl;
    ARRAY ourArray = myArray;
    cout<<"Output after copyconstructor called\n";
    cout<<ourArray<<endl<<endl;

        return 0;
}

Answer 1

您没有退回返回类型：

friend ostream& operator<<(ostream &, ARRAY &);

Answer 2

正如Carl Norum在他的解决方案中提到的那样

You left off the return type:

friend ostream& operator<<(ostream &, ARRAY &);

您也从

中删除了inline

inline ARRAY::~ARRAY()
{

    cout<<"Destructor Called\n";
    delete [ ] DB;
}

是

ARRAY::~ARRAY()
    {

        cout<<"Destructor Called\n";
        delete [ ] DB;
    }

尝试实现运算符时出错[＆！ - ？ - >

2 个答案: