如何使用c#</string>将List <string>响应作为xml文档传递

时间:2013-09-14 04:35:29

标签: c# xml string list

我想将List响应作为xml文档传递,并希望将其作为xml加载。 目前我正在使用此代码执行它:

List<string> BugWSResponseList1 = new List<string>();
BugWSResponseList1 = CreateBugs(FilePath_EXPRESS_API_BugAdd_CreateBugs_DataFile, newValue);
XmlDocument xd = new XmlDocument();
//string s = string.Join(",", BugWSResponseList2);
//xd.LoadXml(s);                    
string s = "<Bugs>" + string.Join(",", BugWSResponseList1) + "</Bugs>";
xd.LoadXml(s);

//Dictionary Creation for Benchmark API                  
XmlDocument ResponseNode_bugs = null;
ResponseNode_bugs = new DrWatsonCore().LoadXMLDocument(s);

我想避免首先将List<string>响应转换为字符串,然后将其作为xml加载。 请建议我如何实现这一目标。

请查看我的LoadXMLDocument功能的详细信息,如下所示:

public XmlDocument LoadXMLDocument(string XMLData)
{
    XmlDocument doc = new XmlDocument();
    try
    {
        doc.LoadXml(XMLData);
    }
    catch (Exception ex)
    {
        Logger.Write("\n\n" + DateTime.Now + " : " + "LoadXMLDocument : SEVERE ERROR : Failed to create XMLDocument from given string : \n\n");
        Logger.Write("\n\n" + DateTime.Now + " : " + "Exception : : \n\n" + ex.Message);
        Logger.Write("\n\n" + DateTime.Now + " : " + "Given String : : \n\n");

        if (DrWatsonHome.doVerboseLogging)
        {
            Logger.Write(XMLData);

        }
        else
        {
            string Response = XMLData;
            Logger.Write("\n\n" + DateTime.Now + " : " + "Response Length : " + Response.Length + " characters.");
            int ResponseLengthToPrint = DrWatsonHome.VerboseLogging_Length_Chars < Response.Length ? DrWatsonHome.VerboseLogging_Length_Chars : Response.Length;
            Logger.Write("\n\n" + DateTime.Now + " : " + "Response : " + Response.Substring(0, ResponseLengthToPrint) + " ...");
        }
    }
    finally
    {
    }

    return doc;
}

我可以在对其进行一些修改后实现它。请建议。

我现在正在使用List,我的功能如下:

List<XElement> Sairam(string FilePath, string Timestamp)
{
    List<XElement> WSResponse = new List<XElement>();

    XmlDocument XDoc = new DrWatsonCore().LoadXMLFromFile(FilePath);
    XmlNode BugListNode = XDoc.SelectSingleNode("/DrWatson/Bugs");
    List<Bug> BugList = new DrWatsonCore().GetBugList(BugListNode);
    List<Thread> BugFtecherThreadList = new List<Thread>();
    foreach (Bug bug in BugList)
    {
        bug.FoundInBuild = Timestamp;
        string URL = new DrWatsonCore().CreateWXURL(EXPRESS_API_METHOD.bug_add, bug, REST_EndPoint, AppGUID, new WatsonUser(Username_Watson, Password_Watson));
        string Response = string.Empty;
        object URLobj = (object) URL;
        Response = CreateBug(URLobj);
        // WSResponse.Add(Response);

    }

    return WSResponse;
}

我想将WSResponse作为程序的最终响应,但我无法获取它。请建议如何从此功能获得该程序的响应。

0 个答案:

没有答案