使用matplotlib中的pcolormesh例程动画,如何初始化数据?

时间:2013-09-14 00:42:07

标签: python animation matplotlib multidimensional-array

我正在尝试为pcolormesh中的matplotlib设置动画。我见过许多使用包动画的例子,其中大多数使用一维绘图例程,其中一些使用imshow()。 首先,我想使用FuncAnimation routine。我的问题是,首先,我不知道我是否可以初始化情节

fig,ax = plt.subplots()
quad = ax.pcolormesh(X,Y,Z)

我尝试了几个简单的界限:

fig,ax = plt.subplots()
quad = ax.pcolormesh([])

def init():
    quad.set_array([])
    return quad,

def animate(ktime):  
    quad.set_array(X,Y,np.sin(Z)+ktime)
return quad,

anim = animation.FuncAnimation(fig,animate,init_func=init,frames=Ntime,interval=200,blit=True)

plt.show()

顺便说一句,如何设置标签和动画情节?如果标题显示的是时间变化的数字,我可以为标题设置动画吗? 感谢

4 个答案:

答案 0 :(得分:9)

问题在于我错误地使用set_array()例程。请务必注意,必须将1D数组传递给此例程。为此,关于该颜色,pcolormesh等通常绘制多维数组,您应该使用.ravel()。 更重要的是:为了同时为不同的地块制作动画,blitz处的animate.FuncAnimation选项必须为False(请参阅此{{3的“动画选定的地图元素”一节) }})。

这里我发布了带有各种子图的简单程序的代码:

import matplotlib.pyplot as plt
import numpy as np
import matplotlib.gridspec as gridspec
import matplotlib.animation as animation

y, x = np.meshgrid(np.linspace(-10, 10,100), np.linspace(-10, 10,100))

z = np.sin(x)*np.sin(x)+np.sin(y)*np.sin(y)

v = np.linspace(-10, 10,100)
t = np.sin(v)*np.sin(v)
tt = np.cos(v)*np.cos(v)
###########

fig = plt.figure(figsize=(16, 8),facecolor='white')
gs = gridspec.GridSpec(5, 2)
ax1 = plt.subplot(gs[0,0])

line, = ax1.plot([],[],'b-.',linewidth=2)
ax1.set_xlim(-10,10)
ax1.set_ylim(0,1)
ax1.set_xlabel('time')
ax1.set_ylabel('amplitude')
ax1.set_title('Oscillationsssss')
time_text = ax1.text(0.02, 0.95, '', transform=ax1.transAxes)

#############################
ax2 = plt.subplot(gs[1:3,0])
quad1 = ax2.pcolormesh(x,y,z,shading='gouraud')
ax2.set_xlabel('time')
ax2.set_ylabel('amplitude')
cb2 = fig.colorbar(quad1,ax=ax2)

#########################
ax3 = plt.subplot(gs[3:,0])
quad2 = ax3.pcolormesh(x, y, z,shading='gouraud')
ax3.set_xlabel('time')
ax3.set_ylabel('amplitude')
cb3 = fig.colorbar(quad2,ax=ax3)

############################
ax4 = plt.subplot(gs[:,1])
line2, = ax4.plot(v,tt,'b',linewidth=2)
ax4.set_xlim(-10,10)
ax4.set_ylim(0,1)

def init():
    line.set_data([],[])
    line2.set_data([],[])
    quad1.set_array([])
    return line,line2,quad1

def animate(iter):
    t = np.sin(2*v-iter/(2*np.pi))*np.sin(2*v-iter/(2*np.pi))
    tt = np.cos(2*v-iter/(2*np.pi))*np.cos(2*v-iter/(2*np.pi))
    z = np.sin(x-iter/(2*np.pi))*np.sin(x-iter/(2*np.pi))+np.sin(y)*np.sin(y)
    line.set_data(v,t)
    quad1.set_array(z.ravel())
    line2.set_data(v,tt)
    return line,line2,quad1

gs.tight_layout(fig)

anim = animation.FuncAnimation(fig,animate,frames=100,interval=50,blit=False,repeat=False)
plt.show()

print 'Finished!!'

答案 1 :(得分:5)

使用QuadMesh.set_array()时需要注意一些丑陋的细节。如果使用X,Y和C对QuadMesh进行实例化,则可以使用set_array()更新值C.但是set_array不支持与构造函数相同的输入。阅读消息来源表明您需要通过a 1d-array而更令人费解的是,取决于5 8 7 setting,您可能需要cut of your array shading

修改:关于C令人困惑的数组大小甚至有a very old bug report

这意味着:

使用带有着色='flat'的QuadMesh.set_array()

'flat'是shading='flat'的默认值。

shading

看起来像:

resulting graphic with shadig=flat

请注意,如果省略# preperation import numpy as np import matplotlib.pyplot as plt plt.ion() y = np.linspace(-10, 10, num=1000) x = np.linspace(-10, 10, num=1000) X, Y = np.meshgrid(x, y) C = np.ones((1000, 1000)) * float('nan') # intantiate empty plot (values = nan) pcmesh = plt.pcolormesh(X, Y, C, vmin=-100, vmax=100, shading='flat') # generate some new data C = X * Y # necessary for shading='flat' C = C[:-1, :-1] # ravel() converts C to a 1d-array pcmesh.set_array(C.ravel()) # redraw to update plot with new data plt.draw() ,您的遗嘱将会显示:

broken graphic with shading=flat

使用带有着色的QuadMesh.set_array()='gouraud'

C = C[:-1, :-1]

如果你用shade ='gouraud'切掉最后一行/列,你会得到:

# preperation (same as for 'flat')
import numpy as np
import matplotlib.pyplot as plt
plt.ion()
y = np.linspace(-10, 10, num=1000)
x = np.linspace(-10, 10, num=1000)
X, Y = np.meshgrid(x, y)
C = np.ones((1000, 1000)) * float('nan')

# intantiate empty plot (values = nan)
pcmesh = plt.pcolormesh(X, Y, C, vmin=-100, vmax=100, shading='gouraud')

# generate some new data
C = X * Y

# here no cut of of last row/column!

# ravel() converts C to a 1d-array
pcmesh.set_array(C.ravel())

# redraw to update plot with new data
plt.draw()

答案 2 :(得分:3)

我不确定你的quad = ax.pcolormesh(X,Y,Z)函数为什么会出错。你能发布错误吗?

以下是使用pcolormesh创建简单动画的方法:

import matplotlib.pyplot as plt
import numpy as np

y, x = np.meshgrid(np.linspace(-3, 3,100), np.linspace(-3, 3,100))

z = np.sin(x**2+y**2)
z = z[:-1, :-1]

ax = plt.subplot(111)

quad = plt.pcolormesh(x, y, z)

plt.colorbar()

plt.ion()
plt.show()

for phase in np.linspace(0,10*np.pi,200):
    z = np.sin(np.sqrt(x**2+y**2) + phase)
    z = z[:-1, :-1]

    quad.set_array(z.ravel())
    plt.title('Phase: %.2f'%phase)
    plt.draw()

plt.ioff()
plt.show()

其中一个框架:enter image description here

这有帮助吗?如果没有,也许你可以澄清这个问题。

答案 3 :(得分:0)

还有另一个答案here看起来更简单(恕我直言)

这是一份副本&粘贴替代解决方案:

import matplotlib.pylab as plt
from matplotlib import animation

fig = plt.figure()

plt.hold(True)
#We need to prime the pump, so to speak and create a quadmesh for plt to work with
plt.pcolormesh(X[0:1], Y[0:1], C[0:1])

anim = animation.FuncAnimation(fig, animate, frames = range(2,155), blit = False)

plt.show()
plt.hold(False)

def animate( self, i):
    plt.title('Ray: %.2f'%i)
    #This is where new data is inserted into the plot.
    plt.pcolormesh(X[i-2:i], Y[i-2:i], C[i-2:i])