Question

我已经在这里待了几个小时!!!!对赋值的更新声明我们需要在值超过100时停止用户输入。如果不重写整个内容，我该如何“循环”它？我知道代码方法很重，但这是分配的要求。我想我的大脑只是java汤！任何帮助都会很棒：）

public static void main(String[] args) {
    //Use Main Method for gathering input
    float input = 1;
    // Declare variable for sum
    float theSum = 0;
    // Declare variable for average
    float average = 0;
    // Declare variable for counting the number of user inputs
    int counter = 0;
    /* Initialize the while loop using an input of 0 as a sentinel value
     * to exit the loop*/
    while (input != 0) {
        // Use JOptionPane method to accept input from user
        input = Float.parseFloat(
                JOptionPane.showInputDialog(
                null, "Please enter a number.  Enter 0 to quit: "));
        // Invoke sum method and pass input and summation to sum method
        theSum = (sum(input, theSum));
        // Invoke avg method and pass summation and counter to avg
        average = (avg(theSum, counter));
        // Increment the counter variable
        counter++;
    }
    // Invoke display method and pass summation, average, and counter variables to it
    display(theSum, average, counter);
}
public static float sum(float num1, float sum) {
    //Add the user's input number to the sum variable
    sum += num1;

    //Return value of sum variable as new summation variable
    return sum;
}
public static float avg(float num1, int num2) {
    //Declare and initialize variable for average
    float average = 0;

    //Calculate average
    average = num1 / num2;

    //Return value of average variable
    return average;
}
public static void display(float sum, float average, int counter) {

    /* I am subtracting 1 from variable counter so as not to include the sentinel value
     * of 0 that the user had to enter to exit the input loop in the overall count*/

    // Display the count, sum, and average to the user
    JOptionPane.showMessageDialog(null, "Count = " + (counter - 1) + ", Sum = " + sum + ", Average = " + average);

    // Test to see if sum is greater than 100 and if so, display alert to user
    if (sum > 100) {
        JOptionPane.showMessageDialog(null, "The sum of your numbers is greater than 100!");
    }
}

}

如果我在计数器后输入此信息++用户在第一次输入后收到此消息...我做错了什么!!!!!!

if (theSum > 100)
            break;
                JOptionPane.showMessageDialog(null, "The sum of your numbers is greater than 100!");

中断的问题是“JOptionPane.showMessageDialog（null，”你的数字的总和大于100！“）;”一段代码导致了一些输出问题休息后立即放置。现在麻烦的是，总和> 100的平均值是输出总和而不是平均值。总和＆lt; = 100 ... WTH可以正常工作吗？！？！：）

现在是代码：

public static void main(String[] args) {
    //Use Main Method for gathering input
    float input = 1;
    // Declare variable for sum
    float theSum = 0;
    // Declare variable for average
    float average = 0;
    // Declare variable for counting the number of user inputs
    int counter = 0;
    /* Initialize the while loop using an input of 0 as a sentinel value
     * to exit the loop*/
    while (input != 0) {
        // Use JOptionPane method to accept input from user
        input = Float.parseFloat(
                JOptionPane.showInputDialog(
                null, "Please enter a number.  Enter 0 to quit: "));
        // Invoke sum method and pass input and summation to sum method
        theSum = (sum(input, theSum));
        // Invoke avg method and pass summation and counter to avg
        average = (avg(theSum, counter));
        // Increment the counter variable
        counter++;

        if (theSum > 100)
            break;                                
    }
    // Invoke display method and pass summation, average, and counter variables to it
    display(theSum, average, counter);
}
public static float sum(float num1, float sum) {
    //Add the user's input number to the sum variable
    sum += num1;        
    //Return value of sum variable as new summation variable
    return sum;
}
public static float avg(float num1, int num2) {
    //Declare and initialize variable for average
    float average = 0;
    //Calculate average
    average = num1 / num2;
    //Return value of average variable
    return average;
}
public static void display(float sum, float average, int counter) {

    /* I am subtracting 1 from variable counter so as not to include the sentinel value
     * of 0 that the user had to enter to exit the input loop in the overall count*/

    // Display the count, sum, and average to the user
    if (sum >100)
    JOptionPane.showMessageDialog(null, "Count = " + (counter) + ", Sum = " + sum + ", Average = " + average);
    if (sum <= 100)
    JOptionPane.showMessageDialog(null, "Count = " + (counter-1) + ", Sum = " + sum + ", Average = " + average);

    }
}

Answer 1

在break循环中使用while语句并if条件检查 thesum > 100。希望这一点提示能帮助你获得理想的行为。因为你还需要计算平均值，所以把断开逻辑放在avg：

之后

     while (input != 0) {
    // Use JOptionPane method to accept input from user
    input = Float.parseFloat(
            JOptionPane.showInputDialog(
            null, "Please enter a number.  Enter 0 to quit: "));
    // Invoke sum method and pass input and summation to sum method
    theSum = (sum(input, theSum));
    // Invoke avg method and pass summation and counter to avg
    average = (avg(theSum, counter));
    // Increment the counter variable
    counter++;
    if (theSum > 100)
      break;
}
// Invoke display method and pass summation, average, and counter variables to it
display(theSum, average, counter);

Answer 2

将循环更改为

do { ... } while (input != 0 && sum < 100);

在循环停止之前，您无需计算平均值。

当总和超过100并且仍然预先形成总和和平均值时，如何让此代码停止输入？

2 个答案: