Question

我正在使用Symfony2和FOSUserBundle，我想使用Ajax进行用户登录。我使用扩展DefaultAuthenticationFailureHandler类的服务：

<?php
namespace Marquis\WebsiteBundle\Handler;

use Psr\Log\LoggerInterface;
use Symfony\Component\Translation\Translator;
use Symfony\Component\HttpFoundation\JsonResponse;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpKernel\HttpKernelInterface;
use Symfony\Component\Security\Core\Exception\AuthenticationException;
use Symfony\Component\Security\Http\Authentication\DefaultAuthenticationFailureHandler;
use Symfony\Component\Security\Http\HttpUtils;

class AuthenticationFailureHandler extends DefaultAuthenticationFailureHandler {

    protected $translator;

    public function __construct(HttpKernelInterface $httpKernel, HttpUtils $httpUtils, array $options, LoggerInterface $logger = null, Translator $translator = null) {
        parent::__construct($httpKernel, $httpUtils, $options, $logger);

        $this->translator = $translator;
    }

    public function onAuthenticationFailure(Request $request, AuthenticationException $exception) {
        if($request->isXmlHttpRequest()) {
            /* @var $formResponse RedirectResponse */
            $formResponse = parent::onAuthenticationFailure($request, $exception);
            $response = new JsonResponse(array('success' => false,
                'message' => $this->translator->trans($exception->getMessage(), array(), 'FOSUserBundle'),
                'form' => $formResponse->getTargetUrl()));
        } else {
            $response = parent::onAuthenticationFailure($request, $exception);
        }

        return $response;
    }
}

它工作得很好，但我希望将渲染视图转换为'form'JsonResponse值。

是否可以从RedirectResponse对象生成视图？

Answer 1

如果我理解正确，你想渲染一个视图并在登录或注册页面上显示该视图吗？

如果是这样，您可以直接返回您的视图，并从javascript代码解析为html并附加到您想要的任何位置。

return $this->twig->render("SampleBundle:sample.html.twig", $data); //$data is not required

你可以像这样将加载的html附加到容器中;

$.ajax({
  dataType:"html",
  success: function(response){
    response.append('#container');
  }
});

Symfony2 AuthenticationFailureHandler - 来自RedirectResponse的JSON renderView

1 个答案: