Question

我有以下课程：

class User {
  hasMany = [ratings: Rating] 
} 

class Item {
 hasMany = [ratings: Rating]
}

class Rating {
 belongsTo = [user: User, item: Item]
}

我想计算对商品评分的不同用户。

以下不起作用：

select count(distinct(r.user)) from Rating as r
        where r.item=:item
        group by r.user

如何修改HQL查询以使其正常工作？

Answer 1

您的查询应该按预期工作，只需稍微修改您使用distinct的方式：

select count(distinct r.user) from Rating as r 
where r.item = :item group by r.user

执行此查询的另一种方法是使用User和join：

select count(distinct u) from User as u 
inner join u.ratings as r where r.item = :item
group by r.user

Answer 2

这是在Hibernate Criteria中的方法

Criteria crit = session.createCriteria(Rating.class)
.add(Restrictions.like("item", item)
.addOrder(Order.asc("user"))
.setProjection(
       Projections.distinct(Projections.projectionList()
                        .add(Projections.property("user"), "user")))
.setResultTransformer(Transformers.aliasToBean(Rating.class));

Answer 3

只需在交易中运行查询。

Transaction tx=session.beginTransaction;
//Run your query here
tx.commit();

问题出现是因为hibernate缓存。

Hibernate HQL Count Distinct不工作？

3 个答案: