Question

在foreach循环中通过标记读取xml 示例xml：

<users>
 <user>
  <id>12345567</id> 
  <name>Ronsna Stedinberg</name> 
 </user>
 <user>
  <id>12345568</id> 
  <name>Sonsna Dtedinberg</name> 
 </user>  
</users>

现在我想将标签保存到包含所有子标签的新文件

Answer 1

这是循环用户节点的方式

string xml = @"<users><user><id>12345567</id><name>Ronsna Stedinberg</name></user><user><id>12345568</id><name>Sonsna Dtedinberg</name></user></users>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);

XmlNodeList nodeList = doc.SelectNodes("//users/user");
foreach (XmlNode node in nodeList)
{
    string id = node.SelectSingleNode("id").InnerText;
    string name = node.SelectSingleNode("name").InnerText;
}

Answer 2

Linq to XML方法：

// Assuming your xml is named data.xml
XDocument xml = XDocument.Load("data.xml");

var tags = from x in xml.Descendants("user")                       
               select new
               {
                   id = x.Element("id").Value,
                   name = x.Element("name").Value
               };

foreach (var tag in tags)
{
    Console.WriteLine(tag.id);
    Console.WriteLine(tag.name);
}

通过标记和写作来读取xml

2 个答案: