Question

有没有办法完全反向匹配我使用的正则表达式。

(?!...)仅适用于简单模式。我的意思是我有一个RegEx来匹配多种格式，但我想替换除多种格式之外的字符串中的所有内容。

比如说：我写了一个复杂的RegEx模式来查找工作日，小时，月，年。而不是找到这些匹配并使用这些模式拆分我的字符串并加入匹配的所有内容;如果有反向匹配，我可以直接替换它。

How to "inverse match" with regex?中给出的解决方案并不支持所有内容。

示例

hr = """
Monday: 11:30am - 9:30pm Tuesday: 11:30am - 9:30pm
Wednesday: 11:30am - 10:00pm Thursday: 11:30am - 10:00pm 
Friday: 11:30am - 10:30pm Saturday: 11:00am - 10:30pm
(brunch served until 3pm) Sunday: 10:30am - 9:30pm (brunch served until 3pm)
Happy Hour and Special Appetizer menu starting at $3 in the bar. Hours from 4 - 7pm Daily.
$4 BURGER special available on Monday. Wednesday: 1/2 off all bottled wines (4-close)"""


import re

newStr = []
dayPattern = """
   (?:mon|tue|wed|thu|fri|sat|sun|thurs)(?:day)?(?:[.:])*
   \s*
   (?:\d{1,2}(?:[:]\d{1,2})?)\s*(?:[ap][.]?m.?) # Start hour
   \s*[-|to]+\s*
  (?:\d{1,2}(?:[:]\d{1,2})?)\s*(?:[ap][.]?m.?) # Close   hour
 """

newStr.extend(\
    re.findall(re.compile(dayPattern, re.VERBOSE|re.IGNORECASE), hr))

print " ".join(newStr)

输出

Monday: 11:30am - 9:30pm  Thursday: 11:30am - 10:00pm  Friday: 11:30am - 10:30pm  Sunday: 10:30am - 9:30pm

但在这里我缺少"Monday: 11:30am - 9:30pm Tuesday: 11:30am - 9:30pm Wednesday: 11:30am - 10:00pm Thursday: 11:30am - 10:00pm Friday: 11:30am - 10:30pm"。

我可以修改我的正则表达式以包含此模式

但是除了星期一/星期二之外，有没有办法可以删除任何单词....＆amp;周一/周二/周三......＆amp; 11:00 am/12pm ...

，即我想要的是这个输出： Monday: 11:30am - 9:30pm Tuesday: 11:30am - 9:30pm Wednesday: 11:30am - 10:00pm Thursday: 11:30am - 10:00pm Friday: 11:30am - 10:30pm Saturday: 11:00am - 10:30pm Sunday: 10:30am - 9:30pm

Answer 1

我不明白你做反向正则表达式的意图。 findall()似乎是选择时间的自然方式，如下所示：

' '.join(re.findall(r'\w{3,6}day:\s*\d{1,2}:\d{1,2}[ap]m\s*-\s*\d{1,2}:\d{1,2}[ap]m', hr))

它产生：

'Monday: 11:30am - 9:30pm Tuesday: 11:30am - 9:30pm Wednesday: 11:30am - 10:00pm Thursday: 11:30am - 10:00pm Friday: 11:30am - 10:30pm Saturday: 11:00am - 10:30pm Sunday: 10:30am - 9:30pm'

Python中的负RegEx模式匹配等效于Perl（！〜运算符）

1 个答案: