Question

我是C的新手，我正在开展一个项目，我一直在努力工作几天，我无法弄清楚问题出在哪里。

基本上，应用程序应该做的是从数据库读取数据并将值插入到结构中。有些行与每个行相关，因此在结构中是一个链表，它将包含数据库中的其他值。

我不知道我将从数据库中获取多少条记录，因此我最初将结构malloc为100项，并且我跟踪索引，如果它达到100，则将结构重新分配给再添加100个项目。重新分配位似乎工作，但这就是为什么我尝试在结构中插入一些东西，我得到一个段错误。

以下是主要结构的定义。

typedef struct CallLogSearchDataStruct
{
    char * date;
    char * time;
    char * bParty;
    char * aParty;
    float duration;
    char * cleardownCause;
    struct CallLogSearchOutboundStruct * outboundLegs;
} callLogSearchDataStruct;

以下是链接列表的代码（CallLogSearchOutboundStruct）

typedef struct CallLogSearchOutboundStruct
{
    char * target;
    float duration;
    char * cleardownCause;
    struct CallLogSearchOutboundStruct * nextLeg;
} callLogSearchOutboundStruct;

我使用以下代码初始化结构

callLogSearchData = calloc(INITIAL_CALL_STRUCT_SIZE,sizeof(callLogSearchDataStruct));
callLogSearch = calloc(INITIAL_CALL_STRUCT_SIZE,sizeof(callLogSearchResultStruct));
switches = calloc(INITIAL_CALL_STRUCT_SIZE, sizeof(switchIDStructure));

每次循环数据时，我都使用以下代码对结构中的outboundLeg链表进行malloc

if (dataRow > -1 && callLogSearchData[dataRow].outboundLegs == NULL)
                {
                    //Initialise the outbound struct
                    callLogSearchData[dataRow].outboundLegs = malloc(sizeof(callLogSearchOutboundStruct));
                    callLogSearchData[dataRow].outboundLegs->cleardownCause = NULL;
                    callLogSearchData[dataRow].outboundLegs->duration = 0;
                    callLogSearchData[dataRow].outboundLegs->target = NULL;
                    callLogSearchData[dataRow].outboundLegs->nextLeg = NULL;
                }
            outboundCallLegStartPtr = callLogSearchData[dataRow].outboundLegs;
            outboundCallLegStartPtr->nextLeg = NULL;

下面是调用函数将数据插入结构

中的链表的代码

insertOutboundLegToList(outboundCallLegStartPtr, targetBuffer, durationBuffer, atoi(rowReport[cleardownColIndex]), debugFile);

以下是实际插入功能的代码

void insertOutboundLegToList(callLogSearchOutboundStruct * outboundLeg, char * target, float duration, int cleardown, FILE * debugFile)
{
    //fprintf(debugFile, "INSIDE INSERT OUTBOUND LEG FUNCTION\n");
    if (outboundLeg->target == NULL)
    {
        outboundLeg->target = strdup(target);
        outboundLeg->duration = duration;
        outboundLeg->cleardownCause = strdup(setCallResult(cleardown));
        //fprintf(debugFile, "Outbound target is: %s\n", outboundLeg->target);
    }
    else
    {
        while (outboundLeg->nextLeg != NULL)
        {
            outboundLeg = outboundLeg->nextLeg;
        }
        outboundLeg->nextLeg = (callLogSearchOutboundStruct*)malloc(sizeof(callLogSearchOutboundStruct));
        outboundLeg = outboundLeg->nextLeg;
        outboundLeg->target = strdup(target);
        outboundLeg->duration = duration;
        outboundLeg->cleardownCause = strdup(setCallResult(cleardown));
        //fprintf(debugFile, "Outbound target is: %s\n", outboundLeg->target);
        outboundLeg->nextLeg = NULL;
    }


}

下面是我如何调用函数来检查是否需要重新分配结构

if (reallocateStructures(&callLogSearch, &callLogSearchData, &switches, &timesStructHasBeenReallocated, currentStructIndexValue, dataRow) == 0)
                    {
                        //Structures have been reallocated so reset the index
                        currentStructIndexValue = -1;
                    }

以下是重新分配结构的实际功能

int reallocateStructures(callLogSearchResultStruct **callLogSearch, callLogSearchDataStruct ** callLogSearchData, 
        switchIDStructure ** switches, int *timesStructHasBeenReallocated, int currentStructIndexValue,
        int dataRow)
{
    int INITIAL_CALL_STRUCT_SIZE = 100;
    int currentSize = 0;
    int newSize = 0;
    int initFromIndex = 0;
    callLogSearchResultStruct * callLogSearchTemp;
    callLogSearchDataStruct * callLogSearchDataTemp;
    switchIDStructure * switchesTemp;


    printf("Current Struct Index Value: %i\n", currentStructIndexValue);

    if (currentStructIndexValue >= INITIAL_CALL_STRUCT_SIZE) {
        printf("REALLOCATING STRUCTURES");
        currentSize = currentStructIndexValue * *timesStructHasBeenReallocated;

        newSize = currentSize + INITIAL_CALL_STRUCT_SIZE;
        *timesStructHasBeenReallocated = *timesStructHasBeenReallocated + 1;


        callLogSearchTemp = (callLogSearchResultStruct*)realloc(*callLogSearch, (newSize * sizeof(callLogSearchResultStruct)));
        callLogSearchDataTemp = (callLogSearchDataStruct*)realloc(*callLogSearchData, (newSize * sizeof(callLogSearchDataStruct)));
        switchesTemp = (switchIDStructure*)realloc(*switches, (newSize * sizeof(switchIDStructure)));


        /**callLogSearchData = realloc(*callLogSearchData, newSize * sizeof (callLogSearchDataStruct));
        *callLogSearch = realloc(*callLogSearch, newSize * sizeof (callLogSearchResultStruct));
        *switches = realloc(*switches, newSize * sizeof (switchIDStructure));
        */
        for (initFromIndex = currentSize; initFromIndex < newSize; initFromIndex++) {
            callLogSearchDataTemp[initFromIndex].aParty = NULL;
            callLogSearchDataTemp[initFromIndex].bParty = NULL;
            callLogSearchDataTemp[initFromIndex].cleardownCause = NULL;
            callLogSearchDataTemp[initFromIndex].date = NULL;
            callLogSearchDataTemp[initFromIndex].duration = 0;
            callLogSearchDataTemp[initFromIndex].outboundLegs = NULL;
            callLogSearchDataTemp[initFromIndex].time = NULL;

            callLogSearchTemp[initFromIndex].date = NULL;
            callLogSearchTemp[initFromIndex].dRowIndex = dataRow;

            switchesTemp[initFromIndex].switchID = NULL;
        }

        *callLogSearch = callLogSearchTemp;
        *callLogSearchData = callLogSearchDataTemp;
        *switches = switchesTemp;
        return 0;
    }
    else
    {
        return 1;
    }
}

我已经尝试通过Valgrind运行我的程序，但我不完全确定所有消息的意思和做谷歌，虽然我找到了一些东西，但没有帮助我理解这个问题。

来自Valgrind的消息是

==9152== Invalid read of size 4
==9152==    at 0x80544EB: GenerateCallLog (performreport.c:3112)
==9152==    by 0x804AA49: ProcessReport (performreport.c:344)
==9152==    by 0x8056C7E: PerformReportCheck (reportcheck.c:72)
==9152==    by 0x80494D0: main (main.c:82)
==9152==  Address 0x47b22b0 is not stack'd, malloc'd or (recently) free'd
==9152==
==9152== Invalid read of size 4
==9152==    at 0x80545CF: GenerateCallLog (performreport.c:3123)
==9152==    by 0x804AA49: ProcessReport (performreport.c:344)
==9152==    by 0x8056C7E: PerformReportCheck (reportcheck.c:72)
==9152==    by 0x80494D0: main (main.c:82)
==9152==  Address 0x47b22b0 is not stack'd, malloc'd or (recently) free'd
==9152==
==9152== Invalid write of size 4
==9152==    at 0x80545DF: GenerateCallLog (performreport.c:3124)
==9152==    by 0x804AA49: ProcessReport (performreport.c:344)
==9152==    by 0x8056C7E: PerformReportCheck (reportcheck.c:72)
==9152==    by 0x80494D0: main (main.c:82)
==9152==  Address 0x35c is not stack'd, malloc'd or (recently) free'd

Line performreport.c：3112是 if (dataRow > -1 && callLogSearchData[dataRow].outboundLegs == NULL)

performreport.c：3123的行是 outboundCallLegStartPtr = callLogSearchData[dataRow].outboundLegs;

performreport.c：3124的行是outboundCallLegStartPtr->nextLeg = NULL;，它的这一行也在重新分配后导致核心转储

请求的setCallResult函数如下：

char * setCallResult(int callResult)
{
    if (callResult == 1)
    {
        return "Answered";
    }
    else if (callResult != 3)
    {
        return "Unanswered";
    }
    else if (callResult == 3)
    {
        return "Engaged";
    }
    else
    {
        return "N/A";
    }
}

很抱歉，对于所有代码，但我不确切地知道问题的确切位置。查看核心转储，看起来好像有什么东西在摧毁内存，因为当我检查结构中的一些值时，它只是乱码。

感谢您提供的任何帮助。

Answer 1

我可以看到一个潜在的问题：

在insertOutboundLegToList中，您似乎采用第一个条件来表示＆＃34;有一个已分配的结构，但它是空的，但尚未被填充＆＃34;。然后填写，但忘记了NULL nextLeg。因此，假设nextLeg是0x75732d42，因为那里的数据仍在那里;下次调用该函数时，会触发else条件：

while (outboundLeg->nextLeg != NULL)
        {
            outboundLeg = outboundLeg->nextLeg;
        }

现在nextLeg即使它应该是NULL也不是outboundLeg。在一次迭代之后，0x75732d42指向insertOutboundLegToList，即使在那里没有分配的结构。在下一次迭代中，您会因为尝试从无效的内存地址读取而崩溃。

我建议的是（if (outboundLeg->target == NULL) { outboundLeg->target = strdup(target); outboundLeg->duration = duration; outboundLeg->cleardownCause = strdup(setCallResult(cleardown)); // HERE v HERE v HERE v HERE outboundLeg->nextLeg = NULL; ... }）：

*callLogSearchData = callLogSearchData;

此外，realloc函数中的这一行

Temp

可能缺少{{1}}。

具有内存重新分配结构和链表的Segfault

1 个答案: