public async Task<ActionResult> IndexAsync()
{
ShowUploadFiles objFiles = new Helpers.ShowUploadFiles();
ShowComments objComments = new Helpers.ShowComments();
TempData["FileUploaded"] = await objFiles.ShowUploadeFiles();
return View("Index", await objComments.GetListofCommentsfromTable());
}
尝试在我的Controller中实现Async。 我必须调用ShowUploadFiles()来保存在Tempdata中,并调用GetListofCommentsfromTable()并将其作为模型传递。
我如何能够作为Tempdata和Model两者的异步同步加载。
我必须更新为
public async Task<List<BlobModel>> ShowUploadeFilesAsync()
{
//Some operation
return await (List<BlobModel>);
}
答案 0 :(得分:3)
你可以这样做:
public async Task<ActionResult> IndexAsync()
{
ShowUploadFiles objFiles = new Helpers.ShowUploadFiles();
var showUploadeFilesTask = objFiles.ShowUploadeFiles();
ShowComments objComments = new Helpers.ShowComments();
var getListofCommentsfromTableTask = objComments.GetListofCommentsfromTable();
await Task.WhenAll(showUploadeFilesTask, getListofCommentsfromTableTask);
TempData["FileUploaded"] = showUploadeFilesTask.Result;
return View("Index", getListofCommentsfromTableTask.Result);
}