我正在尝试按下按钮上传图像文件。我使用相同的PHP脚本的iOS,它似乎工作正常。我添加了用于上传文件的代码。我怀疑的是我没有正确传递图像文件路径。我已经添加了保存图像文件方法。我只是把它保存为'sign.jpeg'。我没有看到点击按钮上的图像指向uploadfile(查看视图)方法。
public void uploadFile(View view) {
try {
upload("sign.jpeg");
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
实施文件上传的方法
public void upload(String selectedPath) throws IOException {
HttpURLConnection connection = null;
DataOutputStream outputStream = null;
DataInputStream inputStream = null;
String pathToOurFile = selectedPath;
String urlServer = "http://localhost:8888/uploadJava.php";
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
try {
FileInputStream fileInputStream = new FileInputStream(new File(
pathToOurFile));
URL url = new URL(urlServer);
connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type",
"multipart/form-data;boundary=" + boundary);
outputStream = new DataOutputStream(connection.getOutputStream());
outputStream.writeBytes(twoHyphens + boundary + lineEnd);
outputStream
.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";name=\""
+ "sign.jpeg" + "\"" + lineEnd);
outputStream.writeBytes(lineEnd);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
outputStream.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
outputStream.writeBytes(lineEnd);
outputStream.writeBytes(twoHyphens + boundary + twoHyphens
+ lineEnd);
/*int serverResponseCode = connection.getResponseCode();
String serverResponseMessage = connection.getResponseMessage();*/
BufferedReader in = new BufferedReader(
new InputStreamReader(
connection.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
System.out.println(inputLine);
fileInputStream.close();
outputStream.flush();
outputStream.close();
} catch (Exception ex) {
}
}
用于上传文件的php脚本
<?php
$target_path = "./images/";
$target_path = $target_path . basename($_FILES['uploadedfile']['name']);
error_log("Upload File >>" . $target_path . $_FILES['error'] . " \r\n", 3,
"Log.log");
error_log("Upload File >>" . basename($_FILES['uploadedfile']['name']) . " \r\n",
3, "Log.log");
if (move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "The file " . basename($_FILES['uploadedfile']['name']) .
" has been uploaded";
} else {
echo "There was an error uploading the file, please try again!";
}
?>
保存裁剪后从相机拍摄的照片
PictureCallback mPicture = new PictureCallback() {
@Override
public void onPictureTaken(byte[] data, Camera camera) {
InputStream is = new ByteArrayInputStream(data);
Bitmap bmp = BitmapFactory.decodeStream(is);
bmp = Bitmap.createBitmap(bmp, 50, 200, bmp.getWidth() - 200, bmp.getHeight()/2);
saveImage("sign.jpeg", bmp, getApplicationContext());
try {
FileOutputStream fos;
fos= openFileOutput(fileName,Context.MODE_PRIVATE);
System.out.println(data);
fos.write(data);
fos.close();
} catch (Exception e) {
e.printStackTrace();
}*/
finish();
//releaseCamera();
}
};
图片保存方法
private void saveImage(String filename, Bitmap b, Context ctx){
try {
ObjectOutputStream oos;
FileOutputStream out;// = new FileOutputStream(filename);
out = ctx.openFileOutput(filename, Context.MODE_PRIVATE);
oos = new ObjectOutputStream(out);
b.compress(Bitmap.CompressFormat.PNG, 100, oos);
oos.close();
oos.notifyAll();
out.notifyAll();
out.close();
} catch (Exception e) {
e.printStackTrace();
}
}
是的,在AndroidManifest.xml中添加了Internet权限,如下所示
<uses-permission android:name="android.permission.INTERNET"/>
知道上面的代码有什么问题吗?
答案 0 :(得分:0)
首先这样做:
File ourFile = new File(pathToOurFile);
int ourFileLength = (int)ourFile.length();
bufferSize = Math.min(ourFileLength, maxBufferSize);
然后我不得不承认几乎从未使用available()
。
写的应该是#bytesRead
。
for (;;) (
int bytesRead = fileInputStream.read(buffer, 0, bufferSize);
if (bytesRead <= 0) {
break;
}
outputStream.write(buffer, 0, bytesRead);
}
没有notifyAll
(用于对象锁/线程)。
答案 1 :(得分:0)
由于您通过HTTP将文件发送到php,您可以尝试这种方法:
HttpClient client = new DefaultHttpClient();
HttpPost httpPost = new HttpPost("yourdomain.com");
ResponseHandler<String> responseHandler = new BasicResponseHandler();
try {
MultipartEntity entity = new MultipartEntity();
entity.addPart("uploadedfile", new FileBody(new File ("absolute_path_to_file")));
httpPost.setEntity(entity);
String resp = client.execute(httpPost, responseHandler);
} catch (IOException e) {
Log.d("log", e.getMessage(), e);
}
对于这种方法,您需要在构建路径中使用httpmime和httpclient lib:http://hc.apache.org/downloads.cgi