Question

public static void deleteEmployee(int empId) {
        Iterator<Employee> iterator = list1.iterator();
        while (iterator.hasNext()) {
            if (iterator.next().getEmpid() == empId) {
                System.out.println("The name of whose details deleted is  ::");
                iterator.remove();
            }
        }

    }

这里我试图根据员工ID从arraylist中删除节点。但在删除之前我想显示特定员工的详细信息。我怎么能这样做？

Answer 1

如何将员工存储在临时变量中？

public static void deleteEmployee(int empId) {
    Iterator<Employee> iterator = list1.iterator();
    while (iterator.hasNext()) {
        Employee employee = iterator.next();
        if (employee.getEmpid() == empId) {
            System.out.println("The name of whose details deleted is  ::" + employee.getName()); // or whatever property in employee
            iterator.remove();
        }
    }

}

Answer 2

这与Iterator或List无关。

查看Employee：是否有toString()实施打印详细信息？如果没有，它的属性是否有吸气剂？与System.out.println一起使用。

如何从arraylist中显示删除节点？

2 个答案: