Question

我的代码基本上是根据TMDB中的给定关键字检索搜索结果列表（API ver.3，新API）。

public String getPersonSearchResult(String keywords){
        String query = URLEncoder.encode(keywords);
        String TMDB_API_URL = "http://api.themoviedb.org/3/search/person?";
        String TMDB_LIMIT_LIST = "&page=1";
        String TMDB_QUERY = "&query=" + query;

        HttpClient httpclient = new DefaultHttpClient();
        HttpResponse response;
        String responseString = null;

        try
        {
            // ATTEMPT HTTP REQUEST
            String fullUrl = TMDB_API_URL + TMDB_API_KEY + TMDB_QUERY + TMDB_LIMIT_LIST;
            Log.w(APP_TAG, "TRYING [" + fullUrl + "]");

            response = httpclient.execute(new HttpGet(fullUrl));
            StatusLine statusLine = response.getStatusLine();

            if (statusLine.getStatusCode() == HttpStatus.SC_OK)
            {
                ByteArrayOutputStream out = new ByteArrayOutputStream();
                response.getEntity().writeTo(out);
                out.close();
                responseString = out.toString();
            }else{
                // FAILED REQUEST - CLOSE THE CONNECTION
                response.getEntity().getContent().close();
                throw new IOException(statusLine.getReasonPhrase());
            }
        }catch(Exception e){
            Log.w(APP_TAG, e.getLocalizedMessage());
            Log.w(APP_TAG, "FAILED TO RETRIEVE JSON DATA");
        }

        return responseString;
    }

问题是我总是得到406状态代码（不可接受）。当我试图自己运行URL时

http://api.themoviedb.org/3/search/person?api_key=<MY_API_KEY_HERE>&query=jennifer&page=1

它正确显示JSON结果。

我不确定为什么会这样。类似的函数用于从其他源检索JSON值，并且它可以很好地工作。

这是他们关于搜索的API文档：http://docs.themoviedb.apiary.io/#search

有人能指出我正确的方向吗？任何帮助表示赞赏。

Answer 1

一种方法来做到这一点尝试使用builder.scheme

    URIBuilder builder = new URIBuilder();
    builder.setScheme("http").setHost("api.themoviedb.org").setPath("/3/search/person")
        .setParameter("api_key", YOURAPIKEY)
        .setParameter("page", 1)
        .setParameter("query", query)
    URI uri = builder.build();
    HttpGet httpget = new HttpGet(uri);

.....
   response = httpclient.execute(new HttpGet(httpget ));

Answer 2

我想通过添加这个来解决这个问题：

HttpGet getObj = new HttpGet(fullUrl);
getObj.addHeader("Accept", "application/json");

这可能是API特定要求。虽然不确定......

Answer 3

我认为它与你的代码无关......你的代码是完美的。唯一的问题可能是API请求方法。也许他们需要在请求中请求一些特定的标头。试试请求标题，如“（”Accept“，”application / json“）”它可能有用......

Answer 4

试试这个

    String ret = null; try {
        response = httpClient.execute(httpGet);
    } catch (Exception e) {
        e.printStackTrace();
    }

    try {
        ret = EntityUtils.toString(response.getEntity());
    } catch (IOException e) {
        Log.e("HttpRequest", "" + e.getMessage());
    } catch (Exception e) {
        e.printStackTrace();
    }

    return ret;

Android无法检索JSON响应[SC_406]

4 个答案: