我使用php邮件通知我的订阅者新博客帖子 因为我的下面的函数没有发送我决定添加一个错误捕获器,mail()返回true,它显示我的电子邮件地址,但是不发送电子邮件。请帮忙
$sql = "SELECT * FROM subscribers";
while ($ste = mysqli_fetch_array(mysqli_query($con,$sql)))
{
$messager="
<html>
<head>
<title>Check out what's happening on my Blog this week</title>
<body>
";
$date = date("Y-m-d H:i:s",mktime(date("H"),date("i"),date("s"),date("m"),date("d")-7));
$sqli = "SELECT * FROM blog WHERE date > '$date' LIMIT 2";
$res = mysqli_query($con,$sqli);
while ($jw = mysqli_fetch_array($res))
{
$messager = $messager."<h2>$jw[header] by $jw[author]</h2><p>".substr($jw["text"], 0, 250)."..."."</p><br>";
}
$messager = $messager."</body></html>";
// To send HTML mail, the Content-type header must be set
$headers = 'MIME-Version: 1.0' . "\r\n";
$headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";
$headers .= 'From: <no-reply@zinteen.co.uk>';
$headers .= "X-Mailer: PHP/" . phpversion();
$ma= mail("$ste[email]", "Check out what's happening on my Blog this week",
$messager, $headers);
if ($ma)
die("should've worked.".$ste["email"]);
}
}
答案 0 :(得分:0)
答案 1 :(得分:0)
您应该以另一种方式定位报价:
$ma= mail($ste["email"], "Check out what's happening on my Blog this week",
$messager, $headers);
我在你的电子邮件中更改了它们。