Question

我热衷于使用 ServiceStack ，并使用简单的客户服务创建了一个小测试应用程序：

  [Route("/customers/{id}")]
    public class GetCustomer : IReturn<Customer>
    {
        public int Id { get; set; }
    }
    [Route("/customers/search")]
    public class FindCustomers : IReturn<List<Customer>>
    {
        public string LastName { get; set; }
        public int Age { get; set; }
        public string? City { get; set; }
    }

    public class CustomerService : IService
    {
        public object Get(GetCustomer request)
        {
            var db = new WebServDb();
            var customer = db.FirstOrDefault<Customer>("WHERE Id=@0", request.Id);
            return customer;
        }
        public object Get(FindCustomers request)
        {
            var db = new WebServDb();
            var customers = new List<Customer>();
            if (request.City.HasValue)
                customers = db.Fetch<Customer>("WHERE LastName=@0 AND Age=@1 AND City=@2", request.LastName, request.Age, request.City);
            else
                customers = db.Fetch<Customer>("WHERE LastName=@0 AND Age=@1", request.LastName, request.Age);
            return customers;
        }
    }

FindCustomers 请求DTO包含3个可用于搜索客户的属性。根据设置的属性，我需要以不同的方式查询数据库。那么最好的方法是什么？例如，如果我添加另一个属性，例如：

 [Route("/customers/search")]
    public class FindCustomers : IReturn<List<Customer>>
    {
        public string LastName { get; set; }
        public int Age { get; set; }
        public string? City { get; set; }
        public string? ZipCode { get; set; }
    }

到 FindCustomers DTO，我还必须将服务获取方法更改为：

public object Get(FindCustomers request)
{
    var db = new WebServDb();
    var customers = new List<Customer>();
    if (request.City.HasValue && request.ZipCode.HasValue)
       customers = db.Fetch<Customer>("WHERE LastName=@0 AND Age=@1 AND City=@2 AND ZipCode=@3", request.LastName, request.Age, request.City, request.ZipCode);
    else if (request.City.HasValue)
       customers = db.Fetch<Customer>("WHERE LastName=@0 AND Age=@1 AND City=@2", request.LastName, request.Age, request.City);
    else
       customers = db.Fetch<Customer>("WHERE LastName=@0 AND Age=@1", request.LastName, request.Age);
    return customers;
  }

因此，对于我在请求DTO中添加/删除的每个属性，我需要修改获取方法。 有更好的方法吗？检查属性集和查询数据库的更通用的方法是什么？

在 CustomerService FindCustomersByLastNameCity ， FindCustomersByLastNameZipCode 等）以及相应的特定Get方法会更好吗？ >？

Answer 1

拥有特定请求DTO（例如FindCustomersByLastNameCity，FindCustomersByLastNameZipCode ）会更好吗如果可能的话，我会避免这种情况，因为它违反了ServiceStack鼓励的“基于消息的服务”的好处/方法。

有更好的方法吗？
我不知道我是否有“更好的方法”，但下面是我尝试的两种选择。第二个选项仍然是“正在进行的工作”，并且意味着更“抽象”，但我修改它以适应您的示例，并希望激发其他想法。

使用ExpressionVisitor的选项1：

public object Get(FindCustomers request)
{
    var customers = new List<Customer>();

    var ev = OrmLiteConfig.DialectProvider.ExpressionVisitor<Customer>();
    ev.Where(c => c.LastName == request.LastName).And(c => c.Age == request.Age);
    AddOptionalFilters(ev, request);

    customers = Db.Select<Customer>(ev);

    return customers;
}

private void AddOptionalFilters(SqlExpressionVisitor<Customer> expressionVisitor, FindCustomers request)
{
    if (request.City.HasValue)
    { expressionVisitor.Where(c => c.City == request.City); }

    if (request.ZipCode.HasValue)
    { expressionVisitor.Where(c => c.ZipCode == request.ZipCode); }
}

选项2使用Dapper中的SqlBuilder：

public object Get(FindCustomers request)
{
    var customers = new List<Customer>();          

    var sqlAndParams = SqlAndParameters("SELECT * From Customers", request); //this returns a tuple of the sql string and the parameters
    customers = Db.Query<Customer>(sqlAndParams.Item1, sqlAndParams.Item2);

    return customers;
}

public virtual Tuple<String, IDictionary<string, object>> SqlAndParameters(string sql, FindCustomers request)
{
    var builder = new SqlBuilder();
    var selector = builder.AddTemplate(sql);
    var sqlParams = new ExpandoObject() as IDictionary<string, object>;

    builder.Where("LastName=@LastName");
    sqlParams.Add("LastName", request.LastName);

    builder.Where("Age=@Age");
    sqlParams.Add("Age", request.Age);

    if (request.City.HasValue)
    {
        builder.Where("City=@City");
        sqlParams.Add("City", request.City);
    }

    if (request.ZipCode.HasValue)
    {
        builder.Where("ZipCode=@ZipCode");
        sqlParams.Add("ZipCode", request.ZipCode);
    }

    return Tuple.Create(selector.RawSql, sqlParams);
}

ServiceStack服务请求设计

1 个答案: