我的表格中有两列,例如column_A
和column_B
假设column_A
有数据"最佳购买信用卡"并且column_B
已经"信用不接受购买订单",
在这里,我需要匹配两列中的单词并返回匹配单词的数量。
在这种情况下,它应该返回2作为"购买"和"信用"比赛。
任何人都可以建议sql代码来做同样的事情。
请注意:column_a
和column_b
的大小不固定,即两者中的字数可能会发生变化。
答案 0 :(得分:3)
with t as (
SELECT 1 AS ID, 'best buy card credit' column_1,
'credit no take buy order' column_2
FROM DUAL
UNION ALL
SELECT 2 AS ID, 'gaurav is fool' column_1, 'saurabh is fool' column_2
FROM DUAL
)
,t1_column1 as (
SELECT ID, LEVEL AS n, REGEXP_SUBSTR (column_1, '[^ ]+', 1, LEVEL) AS val
FROM t
CONNECT BY REGEXP_SUBSTR (column_1, '[^ ]+', 1, LEVEL) IS NOT NULL
)
,t1_column2 as (
SELECT ID, LEVEL AS n, REGEXP_SUBSTR (column_2, '[^ ]+', 1, LEVEL) AS val
FROM t
CONNECT BY REGEXP_SUBSTR (column_2, '[^ ]+', 1, LEVEL) IS NOT NULL
)
select id, LISTAGG(VAL,',') WITHIN GROUP(ORDER BY VAL ) words ,COUNT(*) "total matched words"
from
(
SELECT DISTINCT t1_column1.ID ID, t1_column1.val val
FROM t1_column1, t1_column2
WHERE t1_column1.ID = t1_column2.ID
AND t1_column1.val = t1_column2.val
)
group by id