Question

我试图在我的预先输入中返回一个json对象，而不仅仅是一个查询。我的想法是在自动完成菜单中传递其他字段，以帮助过滤结果。示例年份，品牌，型号，修剪。 json对象将包含filteredBy字段id和字段值。搜索make时的示例，json对象将包含过滤器字段id“year”和值“2013”加上当前字段id及其值。

目前这可以在下面工作，但只返回一个值。

 return $field.typeahead({
    replace: (uri, query) { 
       return extendURL(uri, "t:input": query);
    }
 }

这就是我尝试这样做的方式。

<input id="year" value="2013"/>
<input id="make" filterBy="year" value="ford"/>
<input id="model" filterBy="ford" value="fusion"/>


 init = function(spec) {
        var $field = $("#" + spec.id),
                filterIdArray = [];

        if (typeof spec.filterId !== 'undefined') {
            filterIdArray = spec.filterId.split(',');
        }

 return $field.typeahead({
    replace: function(uri, query) {
       var params = {};
           params["t:jsonStringField"] = searchField(spec.id, query);
           params["t:jsonStringFilter"] = searchFilter(filterIdArray);

       var stringify = JSON.stringify(params);

       //I'm trying to pass back this stringified json object.  
       return extendURL(uri, stringify);
    }
  }

    //The current search input
    searchField = function(fieldId, query) {
        return {name: fieldId, value: query};
    };

    //Additional fields used to create where clause within searchField
    searchFilter = function(filterIdArray) {
        var array = [];

        //Field Id's and any fields being filtered by
        for (var i = 0; i < filterIdArray.length; i++) {
            var value = $("#" + filterIdArray[i]).val(),
                 name = filterIdArray[i];

            array.push({name: name, value: value});
        };

        return array;
    };

我最终收到以下错误。

“NetworkError：500内部服务器错误 - /TapDemo/sell/createlisting.year:autocomplete?category=aircraft&0=;&1=%22&2=t&3=:&4=j&5 = S和6 =的O＆amp; 7 = N和8 = S和9 = T＆安培; 10 =的R＆amp; 11 = I＆安培; 12 = N＆安培; 13 =克和14 = F＆安培; 15 = I＆安培; 16 = E＆安培; 17 = 1＆安培; 18 = d＆安培; 19 =％22安培; 20 =：＆安培; 21 = {＆安培; 22 =％22安培; 23 = N＆安培; 24 = A＆安培; 25 = M＆安培; 26 = E＆安培; 27 =％22安培; 28 =：安培; 29 =％22安培; 30 = Y＆安培; 31 = E＆安培; 32 = A＆安培; 33 =的R＆amp; 34 =％22及35 =，＆安培; 36 =％22安培; 37 = v＆安培; 38 = A＆安培; 39 = 1＆安培; 40 = U＆安培; 41 = E＆安培; 42 =％22安培; 43 =：＆安培; 44 =％22安培; 45 = 5＆安培; 46 =％22安培; 47 =}＆安培; 48 =，＆安培; 49 =％22安培; 50 = J＆安培; 51 = S＆安培; 52 =的O＆amp; 53 = N＆安培; 54 = S＆安培; 55 = T＆安培; 56 =的R＆amp; 57 = I＆安培; 58 = N＆安培; 59 = G＆安培; 60 = F＆安培; 61 = I＆安培; 62 = 1＆安培; 63 = T＆安培; 64 = E＆安培; 65 =的R＆amp; 66 =％22安培; 67 =：＆安培; 68 = [＆安培; 69 =＆安培; 70 =}“

有人知道我做错了吗？

Answer 1

您需要做的是，将这些值作为json编码发送，并确保将数据解码为数组，这样您就能够处理这些值。

Twitter Typeahead 0.9.3返回json对象

1 个答案: