嗨我想知道在使用angularjs上传它们之前是否有预览图像的方法?我正在使用这个库。 https://github.com/danialfarid/angular-file-upload
感谢。这是我的代码:
template.html
<div ng-controller="picUploadCtr">
<form>
<input type="text" ng-model="myModelObj">
<input type="file" ng-file-select="onFileSelect($files)" >
<input type="file" ng-file-select="onFileSelect($files)" multiple>
</form>
</div>
controller.js
.controller('picUploadCtr', function($scope, $http,$location, userSettingsService) {
$scope.onFileSelect = function($files) {
//$files: an array of files selected, each file has name, size, and type.
for (var i = 0; i < $files.length; i++) {
var $file = $files[i];
$http.uploadFile({
url: 'server/upload/url', //upload.php script, node.js route, or servlet uplaod url)
data: {myObj: $scope.myModelObj},
file: $file
}).then(function(data, status, headers, config) {
// file is uploaded successfully
console.log(data);
});
}
}
答案 0 :(得分:52)
OdeToCode posted great service这个东西。因此,使用这个简单的指令,您可以轻松预览甚至查看进度条:
.directive("ngFileSelect",function(){
return {
link: function($scope,el){
el.bind("change", function(e){
$scope.file = (e.srcElement || e.target).files[0];
$scope.getFile();
});
}
}
它适用于所有现代浏览器!
答案 1 :(得分:33)
<强>的JavaScript 强>
$scope.setFile = function(element) {
$scope.currentFile = element.files[0];
var reader = new FileReader();
reader.onload = function(event) {
$scope.image_source = event.target.result
$scope.$apply()
}
// when the file is read it triggers the onload event above.
reader.readAsDataURL(element.files[0]);
}
<强> HTML 强>
<img ng-src="{{image_source}}">
<input type="file" id="trigger" class="ng-hide" onchange="angular.element(this).scope().setFile(this)" accept="image/*">
这对我有用。
答案 2 :(得分:9)
答案 3 :(得分:5)
// start Picture Preview
$scope.imageUpload = function (event) {
var files = event.target.files;
for (var i = 0; i < files.length; i++) {
var file = files[i];
var reader = new FileReader();
reader.onload = $scope.imageIsLoaded;
reader.readAsDataURL(file);
}
}
$scope.imageIsLoaded = function (e) {
$scope.$apply(function () {
$scope.img = e.target.result;
});
}
<input type='file' ng-model-instant onchange="angular.element(this).scope().imageUpload(event)" />
<img class="thumb" ng-src="{{img}}" />