表格式
id time_stamp
3 2013-09-05 12:00:00
5 2013-09-06 12:00:00
12 2013-09-07 12:00:00
2 2013-09-08 12:00:00
5 2013-09-09 12:00:00
8 2013-09-10 12:00:00
从上表我想要选择min(id),max(id),last id,last time_stamp in single mysql select query statement
需要的输出是:
min max last(val) last(time_stamp)
2 12 8 2013-09-09 12:00:00
我使用了以下查询
select id, min(id),max(id), time_stamp from table order by time_stamp limit 1
我的错误最新ID值为3而不是8
如果低于SQL小提琴,请检查此项 http://www.sqlfiddle.com/#!2/e9cb1/2/0
答案 0 :(得分:6)
以下是一种使用substring_index()
/ group_concat()
技巧的方法:
select min(id), max(id),
substring_index(group_concat(id order by time_stamp desc), ',', 1) as lastid
from table ;
答案 1 :(得分:3)
假设您在问题中错误地提到了最后一次(time_stamp) - 像往常一样获取max,min然后找出子查询中的最后一个id和时间戳,然后您可以加入所有结果都是一行。
MySQL 5.5.32架构设置:
create table t (id int, time_stamp datetime);
insert into t values(3, '2013-09-05 12:00:00');
insert into t values(5, '2013-09-06 12:00:00');
insert into t values(12, '2013-09-07 12:00:00');
insert into t values(2, '2013-09-08 12:00:00');
insert into t values(5, '2013-09-09 12:00:00');
insert into t values(8, '2013-09-10 12:00:00');
查询1 :
SELECT MIN(t.id), MAX(t.id), latest.id, latest.time_stamp
FROM t JOIN (
SELECT t.id, t.time_stamp
FROM t
ORDER BY time_stamp DESC
LIMIT 1) latest
<强> Results 强>:
| MIN(T.ID) | MAX(T.ID) | ID | TIME_STAMP |
|-----------|-----------|----|----------------------------------|
| 2 | 12 | 8 | September, 10 2013 12:00:00+0000 |