我对SQL(使用DB2)不是很熟悉,我试图选择符合以下条件的不同ID:
select distinct a.ID
from DOGTOWN a
where a.DOGTOWNID > 0
and (a.DELIVERYDATE < (CURRENT_TIMESTAMP - 4680 DAYS))
order by a.ID ASC;
这给我留下了4条记录:
2100353550
2100353779
2100356002
2100356008
这些回报很好,但是当我试图这样做时:
select distinct a.ID
from DOGTOWN a
where
a.DOGTOWNID > 2100356002
and a.DELIVERYDATE < (CURRENT_TIMESTAMP - 4680 DAYS)
order by
a.ID ASC
fetch first 3 rows only
我期待在这种情况下记录2100356008但它返回一个空的结果集..
感谢这个伟大社区的所有专家。答案 0 :(得分:0)
没关系,只是比较错误的id ....答案是:
select distinct a.ID
from DOGTOWN a
where
a.ID > 2100356002
and a.DELIVERYDATE < (CURRENT_TIMESTAMP - 4680 DAYS)
order by
a.ID ASC
fetch first 3 rows only