Java阵列列表和黑杰克游戏

时间:2013-09-10 22:35:38

标签: java arrays blackjack

我正在尝试制作一个非常简单的黑杰克游戏,我在从阵列列表中抽取卡片并将它们放入玩家手中时遇到问题,并且经销商手中......

这就是我到目前为止所有愿意提供帮助的人都会非常感激。

我也意识到我很多人都没有以最有效的方式做到这一点......

CARDS ARRAY LIST

import java.util.ArrayList;

public class deck {
    ArrayList<card> deck = new ArrayList<card>();

public deck () {

    deck = new ArrayList<card>();

    //Spades
    deck.add(new card ("2", "Spades"));
    deck.add(new card ("3", "Spades"));
    deck.add(new card ("4", "Spades"));
    deck.add(new card ("5", "Spades"));
    deck.add(new card ("6", "Spades"));
    deck.add(new card ("7", "Spades"));
    deck.add(new card ("8", "Spades"));
    deck.add(new card ("9", "Spades"));
    deck.add(new card ("10", "Spades"));
    deck.add(new card ("2", "Spades"));
    deck.add(new card ("J", "Spades"));
    deck.add(new card ("Q", "Spades"));
    deck.add(new card ("K", "Spades"));
    deck.add(new card ("A", "Spades"));
    //Clubs
    deck.add(new card ("2", "Clubs"));
    deck.add(new card ("3", "Clubs"));
    deck.add(new card ("4", "Clubs"));
    deck.add(new card ("5", "Clubs"));
    deck.add(new card ("6", "Clubs"));
    deck.add(new card ("7", "Clubs"));
    deck.add(new card ("8", "Clubs"));
    deck.add(new card ("9", "Clubs"));
    deck.add(new card ("10", "Clubs"));
    deck.add(new card ("2", "Clubs"));
    deck.add(new card ("J", "Clubs"));
    deck.add(new card ("Q", "Clubs"));
    deck.add(new card ("K", "Clubs"));
    deck.add(new card ("A", "Clubs"));
    //Hearts
    deck.add(new card ("2", "Hearts"));
    deck.add(new card ("3", "Hearts"));
    deck.add(new card ("4", "Hearts"));
    deck.add(new card ("5", "Hearts"));
    deck.add(new card ("6", "Hearts"));
    deck.add(new card ("7", "Hearts"));
    deck.add(new card ("8", "Hearts"));
    deck.add(new card ("9", "Hearts"));
    deck.add(new card ("10", "Hearts"));
    deck.add(new card ("2", "Hearts"));
    deck.add(new card ("J", "Hearts"));
    deck.add(new card ("Q", "Hearts"));
    deck.add(new card ("K", "Hearts"));
    deck.add(new card ("A", "Hearts"));
    //Diamonds
    deck.add(new card ("2", "Diamonds"));
    deck.add(new card ("3", "Diamonds"));
    deck.add(new card ("4", "Diamonds"));
    deck.add(new card ("5", "Diamonds"));
    deck.add(new card ("6", "Diamonds"));
    deck.add(new card ("7", "Diamonds"));
    deck.add(new card ("8", "Diamonds"));
    deck.add(new card ("9", "Diamonds"));
    deck.add(new card ("10", "Diamonds"));
    deck.add(new card ("2", "Diamonds"));
    deck.add(new card ("J", "Diamonds"));
    deck.add(new card ("Q", "Diamonds"));
    deck.add(new card ("K", "Diamonds"));
    deck.add(new card ("A", "Diamonds"));
}

public ArrayList<card> getCards(){
    return deck;
}

public card deal(){
    card one = deck.get((int) (Math.random() * deck.size()));
    deck.remove(one);
    return one;
}

}

PLAYER&amp;经销商手类

这里是我要填写dealPlayer()&amp; dealDealer()有两张来自阵列的随机牌,我现在只是在一个树桩里似乎找不到任何可行的东西...在此先感谢您的帮助,如果我需要发布任何其他信息,请让我知道!

import java.util.ArrayList;

public class dealer {

    deck deck = new deck();
    String dealerTopCardString = "";
    card playerHandCard;
    card dealerHandCard;
    ArrayList<card> dealerHand = new ArrayList<card>();
    ArrayList<card> playerHand = new ArrayList<card>();

public void start() {
    dealerHand = new ArrayList<card>();
    playerHand = new ArrayList<card>();
}

public void dealPlayer() {
    //LOOKING FOR HELP HERE
}

public void dealDealer() {
    //LOOKING FOR HELP HERE
}

public String getPlayerHand() {

    String playerHandString = "";
    for (int i = 0; i < playerHand.size(); i++)
        playerHandCard = playerHand.get(i);
        card card = new card(playerHandCard.getValue(), playerHandCard.getSuit());
        playerHandString += "\n";
        playerHandString += card.getValue();
        playerHandString += "\t";
        playerHandString += card.getSuit();

        return playerHandString;

    }

public String getDealerHand() {

        String dealerHandString = "";
        for (int i = 0; i < dealerHand.size(); i++)
            dealerHandCard = dealerHand.get(i);
            card card = new card(dealerHandCard.getValue(), dealerHandCard.getSuit());
            dealerHandString += "\n";
            dealerHandString += card.getValue();
            dealerHandString += "\t";
            dealerHandString += card.getSuit();

            return dealerHandString;
    }

public String getDealerTopCard(){

    return getDealerTopCard;
}

public int getPlayerHandValue(){

    return getPlayerHandValue;
}

public int getDealerHandValue(){


    return getDealerHandValue;
}

public void resetDealerHand(){
    dealerHand.clear();
}

public void resetPlayerHand(){
    playerHand.clear();
}

}

2 个答案:

答案 0 :(得分:5)

当您发布问题时,say what you have tried通常是最佳做法。这样,其他人可以帮助您了解您可能出错的地方。

我将就如何解决问题向您提供一些一般性建议。如果您在实施它时遇到特定问题,可以提出一个新问题(或根据其相关程度更新此问题)。

在一个真正的二十一点游戏中,你可以将牌组洗牌,然后移除前4张牌。你可以在这里做同样的事情:

  1. Shuffle the ArrayList
  2. 移除前4张牌以放入玩家/经销商手中。 (也许你可以使用remove方法删除套牌中的第一个或最后一个元素。)
  3. 这看起来可能是家庭作业,因此您可能需要使用ArrayList。这不是最好的数据结构。如果您有选择,我会使用ArrayDeque代替。它具有高效的pop()remove()方法,用于从集合中取出第一个或最后一个项目。

    (提示:“deque”代表双端队列,但它的发音是“deck”。这是因为它在概念上就像一副纸牌......)

答案 1 :(得分:3)

使用Collections#shuffle

来洗牌
Collections.shuffle(deck);

然后使用List#remove从牌组顶部获取下一张牌,所以这样就可以处理起手牌了

playerHand.add(deck.remove(0));   // top card to player
dealerHand.add(deck.remove(0));   // top card to dealer
playerHand.add(deck.remove(0));
dealerHand.add(deck.remove(0));