我在Yii上使用FileField。在创建它工作正常,但我有更新的麻烦。
假设有人在文件字段中保存了表单名称城市和图像,但忘记输入类型,因此更新表单,编辑类型并再次保存,这是问题所在。在保存更新时,文件字段删除之前上载的图像。我找到了一些代码,但现在不是保存和删除图像,而是向我发送了这个错误:
致命错误:在非对象上调用成员函数saveAs()。
这是我的表格:
<?php
Yii::app()->user->setFlash('success', '<strong>Well done!</strong> You successfully read this important alert message.');
$this->widget('bootstrap.widgets.TbAlert', array(
'block'=>true, // display a larger alert block?
'fade'=>true, // use transitions?
'closeText'=>'×', // close link text - if set to false, no close link is displayed
'alerts'=>array( // configurations per alert type
'error'=>array('block'=>true, 'fade'=>true, 'closeText'=>'×'), // success, info, warning, error or danger
),
));
?>
<div class="form">
<?php $form=$this->beginWidget('CActiveForm', array(
'id'=>'reportes-form',
'enableAjaxValidation'=>false,
'htmlOptions' => array('enctype' => 'multipart/form-data'),
)); ?>
<?php echo $form->errorSummary($model); ?>
<p class="help-block">Fields with <span class="required">*</span> are required.</p>
<div class="row">
<?php echo $form->labelEx($model, 'name'); ?>
<?php echo $form->textField($model,'name'); ?>
<?php echo $form->error($model, 'name'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model, 'city'); ?>
<?php echo $form->textField($model,'city'); ?>
<?php echo $form->error($model, 'city'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'id_type'); ?>
<?php $datos = CHtml::listData(Types::model()->findAll(array('condition'=>'', 'order'=>'')), 'id', 'name');
echo CHtml::activeDropDownList($model,'id_type',$datos,array('prompt'=>'Select', 'disabled'=> ''));
?>
</div>
<div class="row" >
<?php echo $form->labelEx($model, 'description'); ?>
<?php echo $form->textArea($model,'description'); ?>
<?php echo $form->error($model, 'description'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model, 'image'); ?>
<?php if ($model->image): ?>
<div>Existing image: <?php echo CHtml::encode($model->image); ?></div>
<div>
<img src="<?php echo Yii::app()->request->baseUrl.'/images/uploads/'.$model->image?>" width="180" height="180" />
</div>
<?php endif; ?>
<?php echo $form->fileField($model, 'image'); ?>
<?php echo $form->error($model, 'image'); ?>
</div>
<div class="form-actions">
<?php $this->widget('bootstrap.widgets.TbButton', array(
'buttonType'=>'submit',
'type'=>'primary',
'label'=>$model->isNewRecord ? 'Create' : 'Save',
)); ?>
</div>
<?php $this->endWidget(); ?>
这是我的控制器更新:
public function actionUpdate($id)
{
$model=$this->loadModel($id);
// Uncomment the following line if AJAX validation is needed
// $this->performAjaxValidation($model);
if(isset($_POST['Restaurants']))
{
$model->attributes=$_POST['Restaurants'];
$oldFileName = $_POST['Restaurants']['image'];
$model->image= CUploadedFile::getInstanceByName('Restaurants[image]');
$path = Yii::getPathOfAlias('webroot')."/images/uploads/";
if($model->save()) {
if($model->image == null){
$model->image->saveAs(Yii::getPathOfAlias('webroot')."/images/uploads/".$oldFileName);
$this->redirect(array('view','id'=>$model->id));
}
else
{
$model->image->saveAs(Yii::getPathOfAlias('webroot')."/images/uploads/".$model->image);
chmod( $path.$model->image, 0777 );
$this->redirect(array('view','id'=>$model->id));
}
}
}
$this->render('update',array(
'model'=>$model,
));
}
var_dump
$model->file
null
发送给我$oldFileName
,$model->image
第一次上传图片的名称。所以我猜这应该可以毫无困难地保存{{1}}旧名称。我缺少什么?
答案 0 :(得分:2)
(在评论和修改中回答。见Question with no answers, but issue solved in the comments (or extended in chat))
@Martin Komara写道:
OP写道:我认为很明显,如果
$model->image->saveAs
为$model->image
,则无法致电null
(由于条件原因,这是$model->image = 'path to image'; $model->save();
。你想要实现什么目标?是否要删除之前上传的文件?您需要更新模型,即
public function actionUpdate($id) { $model=$this->loadModel($id); if(isset($_POST['Restaurants'])) { $_POST['Restaurants']['image'] = $model->image; $model->attributes=$_POST['Restaurants']; $uploadedFile=CUploadedFile::getInstance($model,'image'); if($model->save()) { if(!empty($uploadedFile)) // check if uploaded file is set or not { $uploadedFile->saveAs(Yii::getPathOfAlias('webroot')."/images/uploads/".$model->image); } $this->redirect(array('view','id'=>$model->id)); } } $this->render('update',array( 'model'=>$model, )); }
我的更新控制器现在正常工作:
{{1}}