致命错误:在FileField Update上的非对象上调用成员函数saveAs()

时间:2013-09-10 18:18:03

标签: php yii

我在Yii上使用FileField。在创建它工作正常,但我有更新的麻烦。

假设有人在文件字段中保存了表单名称城市和图像,但忘记输入类型,因此更新表单,编辑类型并再次保存,这是问题所在。在保存更新时,文件字段删除之前上载的图像。我找到了一些代码,但现在不是保存和删除图像,而是向我发送了这个错误:

致命错误:在非对象上调用成员函数saveAs()。

这是我的表格:

<?php 
Yii::app()->user->setFlash('success', '<strong>Well done!</strong> You successfully read this important alert message.');
$this->widget('bootstrap.widgets.TbAlert', array(
    'block'=>true, // display a larger alert block?
    'fade'=>true, // use transitions?
    'closeText'=>'×', // close link text - if set to false, no close link is displayed
    'alerts'=>array( // configurations per alert type
        'error'=>array('block'=>true, 'fade'=>true, 'closeText'=>'×'), // success, info, warning, error or danger
    ),
));
?>

<div class="form">

        <?php $form=$this->beginWidget('CActiveForm', array(
        'id'=>'reportes-form',
        'enableAjaxValidation'=>false,
        'htmlOptions' => array('enctype' => 'multipart/form-data'),
        )); ?>
        <?php echo $form->errorSummary($model); ?>
        <p class="help-block">Fields with <span class="required">*</span> are required.</p>

    <div class="row">
        <?php echo $form->labelEx($model, 'name'); ?>
        <?php echo $form->textField($model,'name'); ?>
        <?php echo $form->error($model, 'name'); ?>
    </div>
    <div class="row">
        <?php echo $form->labelEx($model, 'city'); ?>
        <?php echo $form->textField($model,'city'); ?>
        <?php echo $form->error($model, 'city'); ?>
    </div>

    <div class="row">
        <?php echo $form->labelEx($model,'id_type'); ?>
        <?php $datos = CHtml::listData(Types::model()->findAll(array('condition'=>'', 'order'=>'')), 'id', 'name');
            echo CHtml::activeDropDownList($model,'id_type',$datos,array('prompt'=>'Select', 'disabled'=> '')); 
        ?>
    </div>
    <div class="row" >
        <?php echo $form->labelEx($model, 'description'); ?>
        <?php echo $form->textArea($model,'description'); ?>
        <?php echo $form->error($model, 'description'); ?>
    </div>

    <div class="row">

        <?php echo $form->labelEx($model, 'image'); ?>
        <?php if ($model->image): ?>
            <div>Existing image: <?php echo CHtml::encode($model->image); ?></div>
            <div>
                <img src="<?php echo Yii::app()->request->baseUrl.'/images/uploads/'.$model->image?>" width="180" height="180" />
            </div>
        <?php endif; ?>

        <?php  echo $form->fileField($model, 'image'); ?>
        <?php echo $form->error($model, 'image'); ?>
    </div>

<div class="form-actions">
    <?php $this->widget('bootstrap.widgets.TbButton', array(
            'buttonType'=>'submit',
            'type'=>'primary',
            'label'=>$model->isNewRecord ? 'Create' : 'Save',
        )); ?>
</div>

<?php $this->endWidget(); ?>

这是我的控制器更新:

public function actionUpdate($id)
    {   
        $model=$this->loadModel($id);


        // Uncomment the following line if AJAX validation is needed
        // $this->performAjaxValidation($model);

        if(isset($_POST['Restaurants']))
        {
            $model->attributes=$_POST['Restaurants'];
            $oldFileName    = $_POST['Restaurants']['image'];
            $model->image= CUploadedFile::getInstanceByName('Restaurants[image]');
            $path = Yii::getPathOfAlias('webroot')."/images/uploads/";




            if($model->save()) {
                if($model->image == null){

                    $model->image->saveAs(Yii::getPathOfAlias('webroot')."/images/uploads/".$oldFileName);
                    $this->redirect(array('view','id'=>$model->id));
                }
                else
                {
                    $model->image->saveAs(Yii::getPathOfAlias('webroot')."/images/uploads/".$model->image);
                    chmod( $path.$model->image, 0777 );
                    $this->redirect(array('view','id'=>$model->id));


                }

            }
        }

        $this->render('update',array(
        'model'=>$model,
        ));
    }

var_dump $model->file null发送给我$oldFileName$model->image第一次上传图片的名称。所以我猜这应该可以毫无困难地保存{{1}}旧名称。我缺少什么?

1 个答案:

答案 0 :(得分:2)

(在评论和修改中回答。见Question with no answers, but issue solved in the comments (or extended in chat)

@Martin Komara写道:

  

我认为很明显,如果$model->image->saveAs$model->image,则无法致电null(由于条件原因,这是$model->image = 'path to image'; $model->save();。你想要实现什么目标?是否要删除之前上传的文件?

     

检查此维基:http://www.yiiframework.com/wiki/349/how-to-upload-image-photo-and-path-entry-in-datebase-with-update-functionality/

     

您需要更新模型,即public function actionUpdate($id) { $model=$this->loadModel($id); if(isset($_POST['Restaurants'])) { $_POST['Restaurants']['image'] = $model->image; $model->attributes=$_POST['Restaurants']; $uploadedFile=CUploadedFile::getInstance($model,'image'); if($model->save()) { if(!empty($uploadedFile)) // check if uploaded file is set or not { $uploadedFile->saveAs(Yii::getPathOfAlias('webroot')."/images/uploads/".$model->image); } $this->redirect(array('view','id'=>$model->id)); } } $this->render('update',array( 'model'=>$model, )); }

OP写道:

  

我的更新控制器现在正常工作:

{{1}}